在文本中搜索單詞並突出顯示包含它的所有單詞的函數

Question

此函數在文本內搜索單詞（從$ words數組中）並突出顯示它們。

function highlightWords(Array $words, $text){ // Loop through array of words 
    foreach($words as $word){ // Highlight word inside original text 
     $text = str_replace($word, '<span class="highlighted">' . $word . '</span>', $text); 
    }   
    return $text; // Return modified text 
} 

這裏的問題是：

比方說的話$ =陣列（ 「汽車」， 「驅動器」）;

是否有功能突出，不僅字車的方式，而且還包含了字母詞「汽車」，如：汽車，卡爾馬尼亞等

謝謝！

Answer 1

你想要的是（回撥你的情況將被推薦）正則表達式，preg_replace函數或peg_replace_callback更特別

<?php 
$searchString = "The car is driving in the carpark, he's not holding to the right lane.\n"; 

// define your word list 
$toHighlight = array("car","lane"); 

因爲你需要一個正則表達式來搜索你的話，你可能會想要或需要隨着時間的推移變化或變化，將它硬編碼到搜索詞中是不好的做法。因此，最好走路array_map陣列上，改造搜索內容到適當的正則表達式（這裏只是圍住進行/並增加了「接受一切，直到標點」表達）

$searchFor = array_map('addRegEx',$toHighlight); 

// add the regEx to each word, this way you can adapt it without having to correct it everywhere 
function addRegEx($word){ 
    return "/" . $word . '[^ ,\,,.,?,\.]*/'; 
} 

下一步要更換用高亮顯示的版本找到的詞，這意味着您需要動態更改：使用preg_replace_callback而不是常規preg_replace，以便它爲每個找到的匹配調用一個函數，並使用它來生成正確的結果。在這裏，我們在它的跨度標籤

function highlight($word){ 
    return "<span class='highlight'>$word[0]</span>"; 
} 

$result = preg_replace_callback($searchFor,'highlight',$searchString); 

print $result; 

封閉發現字產生

The <span class='highlight'>car</span> is driving in the <span class='highlight'>carpark</span>, he's not holding to the right <span class='highlight'>lane</span>. 

所以才貼上後，其他這些代碼片段，以獲得工作代碼，效果顯着。 ;）

編輯：下面的完整代碼被修改了一些=放在例程中，以方便原始請求者使用。 +不區分大小寫

完整代碼：

<?php 

$searchString = "The car is driving in the carpark, he's not holding to the right lane.\n"; 
$toHighlight = array("car","lane"); 

$result = customHighlights($searchString,$toHighlight); 

print $result; 

// add the regEx to each word, this way you can adapt it without having to correct it everywhere 

function addRegEx($word){ 
    return "/" . $word . '[^ ,\,,.,?,\.]*/i'; 
} 

function highlight($word){ 
    return "<span class='highlight'>$word[0]</span>"; 
} 

function customHighlights($searchString,$toHighlight){ 

// define your word list 
$searchFor = array_map('addRegEx',$toHighlight); 
$result = preg_replace_callback($searchFor,'highlight',$searchString); 
return $result; 

} 

Answer 2

我沒有測試過，但我認爲這應該這樣做： -

$text = preg_replace('/\W((^\W)?$word(^\W)?)\W/', '<span class="highlighted">' . $1 . '</span>', $text); 

這看起來對於一個完整的字有界裏面的字符串，然後使用的preg_replace和定期把跨度周圍一大堆表達式。

Answer 3

function replace($format, $string, array $words) 
{ 
    foreach ($words as $word) { 
     $string = \preg_replace(
      sprintf('#\b(?<string>[^\s]*%s[^\s]*)\b#i', \preg_quote($word, '#')), 
      \sprintf($format, '$1'), $string); 
    } 
    return $string; 
} 


// courtesy of http://slipsum.com/#.T8PmfdVuBcE 
$string = "Now that we know who you are, I know who I am. I'm not a mistake! It 
all makes sense! In a comic, you know how you can tell who the arch-villain's 
going to be? He's the exact opposite of the hero. And most times they're friends, 
like you and me! I should've known way back when... You know why, David? Because 
of the kids. They called me Mr Glass."; 

echo \replace('<span class="red">%s</span>', $string, [ 
    'mistake', 
    'villain', 
    'when', 
    'Mr Glass', 
]); 

正弦它利用周圍的字符串格式sprintf，可以相應地改變你的更換。

_{藉口5.4語法}