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即時通訊目前堆棧如何顯示我的數據庫中的所有數據連接上的jqGrid使用jqGrid的即時通訊新的，我不知道爲什麼我的數據不顯示，當我使用本地主機與MYSQL及ASP.NET
部署於Webgetdata.aspx.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.Configuration;
using System.Web.Services;
using System.Web.Script.Services;
using MySql.Data.MySqlClient;
public partial class getdata : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
public struct s_GridResult
{
public int page;
public int total;
public int record;
public s_RowData[] rows;
}
public struct s_RowData
{
public int id;
public string[] cell;
}
[WebMethod]
public static s_GridResult GetDataTable(string _search, string nd, int rows, int page,
string sidx, string sord)
{
int startindex = (page - 1);
int endindex = page;
string sql = "SELECT ItemCode,PartNumber FROM tblitemcodefromqne";
DataTable dt = new DataTable();
MySqlConnection conn = new
MySqlConnection(ConfigurationManager.ConnectionStrings["ConnectionString1"].ConnectionString);
MySqlDataAdapter adapter = new MySqlDataAdapter(sql, conn);
adapter.Fill(dt);
s_GridResult result = new s_GridResult();
List<s_RowData> rowsadded = new List<s_RowData>();
int idx = 1;
foreach (DataRow row in dt.Rows)
{
s_RowData newrow = new s_RowData();
newrow.id = idx++;
newrow.cell = new string[2]; //total number of columns
newrow.cell[0] = row[0].ToString();
newrow.cell[1] = row[1].ToString();
rowsadded.Add(newrow);
}
result.rows = rowsadded.ToArray();
result.page = page;
result.total = dt.Rows.Count;
result.record = rowsadded.Count;
return result;
}
}
getdata.aspx
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1
/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head id="Head1" runat="server">
<title></title>
<link rel="Stylesheet" type="text/css" media="screen" href="JQGridReq/jquery-
ui-1.9.2.custom.css" />
<link rel="Stylesheet" type="text/css" media="screen" href="JQGridReq/ui.jqgrid.css" />
<link rel="Stylesheet" type="text/css" media="screen" href="Themes/style.css" />
<script type="text/javascript" src="JQGridReq/jquery-1.9.0.min.js"></script>
<script type="text/javascript" src="JQGridReq/jquery.json-2.2.min.js"></script>
<script type="text/javascript" src="JQGridReq/jquery-ui-1.9.4.custom.min.js"></script>
<script type="text/javascript" src="JQGridReq/grid.locale-en.js"></script>
<script type="text/javascript" src="JQGridReq/jquery.jqGrid.js"></script>
<script type="text/javascript" >
$(document).ready(function() {
$.extend($.jgrid.defaults,
{ datatype: 'json' },
{ ajaxGridOptions: { contentType: "application/json",
success: function (data, textStatus) {
if (textStatus == "success") {
var thegrid = $("#Grid1")[0];
thegrid.addJSONData(data.d);
thegrid.grid.hDiv.loading = false;
switch (thegrid.p.loadui) {
case "disable":
break;
case "enable":
$("#load_" + thegrid.p.id).hide();
break;
case "block":
$("#lui_" + thegrid.p.id).hide();
$("#load_" + thegrid.p.id).hide();
break;
}
}
}
}
});
jQuery("#Grid1").jqGrid({
url: 'getdata.aspx/GetDataTable',
datatype: 'json',
mtype: 'POST',
colNames: ['Item Code', 'Part Number'],
colModel: [{ name: 'ItemCode', index: 'ItemCode', width: 200 },
{ name: 'PartNumber', index: 'PartNumber', width: 300}],
pager: '#pager', sortname: 'ItemCode',
viewrecoreds: true,
imgpath: 'JQGridReq/images',
serializeGridData: function (data) {
return $.toJSON(data);
}
});
});
</script>
</head>
<body>
<form id="form1" runat="server">
<table id="Grid1" class="scroll" align="center" width="100%"></table>
<div id="pager" class="scroll" style="text-align:center;">
</div>
</form>
</body>
</html>
問題，如'Please幫幫我吧！「不需額外的幫助這裏堆棧溢出。閱讀FAQ並使用標點符號。 – Mixxiphoid
當然謝謝你。 – CodeNewbie