蟒子：檢查是否執行的腳本要求用戶輸入

Question

import subprocess 

child = subprocess.Popen(['python', 'simple.py'], stdin=subprocess.PIPE) 
child.communicate('Alice') 

我知道通過溝通 你如何檢查腳本「simple.py」是否要求用戶輸入您可以執行腳本交流？

simple.py可能會要求5-10個用戶輸入，所以只需簡單地使用硬編碼communicate就足夠了。

[編輯]：要分析的標準輸出作爲腳本運行並傳送回給腳本

while True: 
    if child.get_stdout() == '?': 
     # send user input 

Answer 1

一個簡單的例子：

simple.py：

i = raw_input("what is your name\n") 
print(i) 
j = raw_input("What is your age\n") 
print(j) 

讀寫：

import subprocess 

child = subprocess.Popen(['python2', 'simple.py'], stdin=subprocess.PIPE, stdout=subprocess.PIPE) 

for line in iter(child.stdout.readline, ""): 
    print(line) 
    if "name" in line: 
     child.stdin.write("foo\n") 
    elif "age" in line: 
     child.stdin.write("100\n") 

輸出：

what is your name 

foo 

What is your age 

100