mysql設置爲空或0，如果右連接返回無行

我有以下查詢不返回行。但是，如果發生這種情況，我想將值設置爲0或null。我該怎麼做呢？mysql設置爲空或0，如果右連接返回無行

UPDATE `hdb`.`projects` 
RIGHT JOIN (
    SELECT jobs.PROJID, round(SUM(jobs.value),2) AS SumOfJobValues, round(Sum(jobs.Earned),2) AS SumOfEarnedValues 
    FROM jobs 
    WHERE projects.PROJID = 1312184 
    GROUP BY jobs.PROJID 
) as temp ON projects.PROJID = temp.PROJID 
SET 
    projects.VALUE = round(SumOfJobValues,2), 
    projects.WIP = round(SumOfEarnedValues,2)

我重寫了我的查詢使用左連接，它在MySQL中工作。然而，當我運行這個使用php Yii框架我不工作。

UPDATE `hdb`.`projects` 
left JOIN (
    SELECT 
    jobs.PROJID, 
    round(SUM(jobs.value),2) AS SumOfJobValues, 
    round(Sum(jobs.Earned),2) AS SumOfEarnedValues 
    FROM jobs   
    GROUP BY jobs.PROJID 
) as temp ON projects.PROJID = temp.PROJID 
SET 
    projects.VALUE = round(SumOfJobValues,2), 
    projects.WIP = round(SumOfEarnedValues,2) 
WHERE projects.PROJID = 1312184

上運行PHP的Yii

$sql = "UPDATE `hdb`.`projects` 
    LEFT JOIN (
    SELECT 
     jobs.PROJID, round(SUM(jobs.value),2) AS SumOfJobValues, 
     round(Sum(jobs.Earned),2) AS SumOfEarnedValues 
    FROM jobs 
    WHERE jobs.PROJID = :pid          
    GROUP BY jobs.PROJID 
    as temp ON projects.PROJID = temp.PROJID        
    SET 
     projects.VALUE = round(SumOfJobValues,2), 
     projects.WIP = round(SumOfEarnedValues,2) 
    WHERE projects.PROJID = :pid"; 

$command=$connection->createCommand($sql); 
$command->bindValue(":pid",$model->PROJID,PDO::PARAM_INT); 
$command->execute();

來源

2013-12-18 shorif2000

爲什麼不只是價值和wip有一個默認值0？ –

'project.VALUE'和'projects.WIP'已經有了值。 '項目'可以有許多'工作'記錄。一旦我刪除了所有的工作記錄，我想更新'項目'中的值，如果可能的話，寧願在1個查詢中執行。 – shorif2000

謝里夫，你爲什麼刪除你自己的答案？這似乎是正確的解決方案。 – RandomSeed

相同的查詢你忘了對你的Yii查詢10號線之前關閉括號。另外，如果你不想加入NULL值，你可以使用「IS NOT NULL」在你的JOIN定義是這樣的：

UPDATE `hdb`.`projects` 
left JOIN (
    SELECT 
    jobs.PROJID, 
    round(SUM(jobs.value),2) AS SumOfJobValues, 
    round(Sum(jobs.Earned),2) AS SumOfEarnedValues 
    FROM jobs   
    GROUP BY jobs.PROJID 
) as temp ON (projects.PROJID = temp.PROJID) AND (temp.PROJID IS NOT NULL) 
SET 
    projects.VALUE = round(SumOfJobValues,2), 
    projects.WIP = round(SumOfEarnedValues,2) 
WHERE projects.PROJID = 1312184

編輯：我沒有測試過這一點，雖然。

來源

2014-01-02 22:45:14

mysql設置爲空或0，如果右連接返回無行

回答

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