2013-03-29 82 views
0

我似乎無法弄清楚如何使tastypie網址工作。 當我在瀏覽器中訪問我的應用程序的根目錄時,debug沒有列出url。 我錯過了什麼?django tastypie網址不起作用

## inventory/models.py 
from django.db import models 
# 
class Server (models.Model): 
    server_id = models.AutoField(primary_key=True) 
    server_name = models.CharField("Server Name",max_length=200,unique=True) 
    server_ip = models.IPAddressField("Server IP") 
    server_serial = models.CharField("Serial No.",max_length=25,null=True,blank=True) 
    server_mem = models.PositiveIntegerField("Mem (MB)",null=True,blank=True) 
    server_architecture = models.ForeignKey(Architecture) 
    server_os = models.ForeignKey(Operating_System) 
    server_os_version = models.CharField("OS Version",max_length="25",null=True,blank=True) 
    server_type = models.ForeignKey(Server_Type,null=True,blank=True) 
    server_mac = models.ForeignKey(Mac,null=True,blank=True) 
    server_digi = models.ForeignKey(Digi,null=True,blank=True) 
    server_digi_port = models.PositiveIntegerField("Digi Port",null=True,blank=True) 
    server_rack = models.ForeignKey(Rack,null=True,blank=True) 
    server_kvm = models.ForeignKey(KVM,null=True,blank=True) 
    def __unicode__(self): 
      return self.server_name 

## inventory/api.py 
from tastypie.resources import ModelResource 
from inventory.models import * 
# 
class ServerResource(ModelResource): 
class Meta: 
    queryset = Server.objects.all() 
    resource_name = 'servers' 

## mmi_assets/urls.py 
from django.conf.urls import patterns, include, url 
# 
## our custom stuff 
from inventory.api import * 
server_resource = ServerResource() 
## 

urlpatterns = patterns('', 
    url(r'^admin/', include(admin.site.urls)), 
    url(r'^inventory/', include('inventory.urls')), 
    url(r'^api/', include(server_resource.urls)), 
) 

回答

1

您需要將資源添加到api,然後包含api的網址。 http://django-tastypie.readthedocs.org/en/latest/tutorial.html#adding-to-the-api

# urls.py 
from django.conf.urls.defaults import * 
from tastypie.api import Api 
from myapp.api import EntryResource, UserResource 

v1_api = Api(api_name='v1') 
v1_api.register(UserResource()) 
v1_api.register(EntryResource()) 

urlpatterns = patterns('', 
    # The normal jazz here... 
    (r'^blog/', include('myapp.urls')), 
    (r'^api/', include(v1_api.urls)), 
)