查詢將不會更新，使用PHP PDO

Question

我的第一個查詢是這樣的：

$sql = "UPDATE application SET userid = ? WHERE appid = ? LIMIT 1"; 

我的第二個查詢是這樣的：

SELECT user.name,application.appid,application.userid,application.created,application.title,application.filesize,application.status,application.apptype 
FROM user,application 
WHERE application.appid = ? LIMIT 1 

然後第二個查詢使用存儲$statement->fetchObject()

問題是$statement->name總是bob。 application.userid是表user中的userid的外鍵。如果我更改表application中的userid，可以說10，則查詢2應該從新的userid上的表user獲得名稱，但問題是它一直告訴我$statement->name是bob。

if (isset($_POST['newowner'])) 
{ 
    $newowner = $_POST['newowner']; 
    $sql = "SELECT COUNT(*) FROM user 
      WHERE userid = ? LIMIT 1"; 
    $statement = $db->prepare($sql); 
    $statement->execute(array($newowner)); 

    if ($statement->fetchColumn() > 0) 
    { 
     $sql = "UPDATE application SET userid = ? 
       WHERE appid = ? LIMIT 1"; 
     $statement = $db->prepare($sql); 
     $statement->execute(array($newowner,$_GET['appid'])); 
     $appdetail->msg = "Owners were successfully changed."; 
     $appdetail->type = "success"; 
    } 
    else 
    { 
     $appdetail->msg = "Could not find client by that userid or email."; 
     $appdetail->type = "warning"; 
    } 
} 
$sql = "SELECT user.name,application.appid,application.userid,application.created,application.title,application.filesize,application.status,application.apptype 
     FROM user,application 
     WHERE application.appid = ? LIMIT 1"; 
$statement = $db->prepare($sql); 
$statement->execute(array($_GET['appid'])); 
$app = $statement->fetchObject(); 

Answer 1

使用PDO，您應該能夠確定有多少行受UPDATE影響。檢查它是否與您希望在測試數據中修改的行數相對應。編輯：this是您需要的聲明。