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說我們產生這樣的字符串:如何將複雜的生成樣式應用於jQuery?
background:#6356ff;
background:url(data:image/svg+xml;
base64,PD94bWwgdmVyc2lvbj0iMS4wIiA/Pgo8c3ZnIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8yMDAwL3N2ZyIgd2lkdGg9IjEwMCUiIGhlaWdodD0iMTAwJSIgdmlld0JveD0iMCAwIDEgMSIgcHJlc2VydmVBc3BlY3RSYXRpbz0ibm9uZSI+CiAgPGxpbmVhckdyYWRpZW50IGlkPSJncmFkLXVjZ2ctZ2VuZXJhdGVkIiBncmFkaWVudFVuaXRzPSJ1c2VyU3BhY2VPblVzZSIgeDE9IjAlIiB5MT0iMCUiIHgyPSIwJSIgeTI9IjEwMCUiPgogICAgPHN0b3Agb2Zmc2V0PSIwJSIgc3RvcC1jb2xvcj0iIzYzNTZmZiIgc3RvcC1vcGFjaXR5PSIxIi8+CiAgICA8c3RvcCBvZmZzZXQ9IjEwMCUiIHN0b3AtY29sb3I9IiM3NWI2ZmYiIHN0b3Atb3BhY2l0eT0iMSIvPgogIDwvbGluZWFyR3JhZGllbnQ+CiAgPHJlY3QgeD0iMCIgeT0iMCIgd2lkdGg9IjEiIGhlaWdodD0iMSIgZmlsbD0idXJsKCNncmFkLXVjZ2ctZ2VuZXJhdGVkKSIgLz4KPC9zdmc+);
background:linear-gradient(top,#6356ff 0%,#75b6ff 100%);
filter:progid:DXImageTransform.Microsoft.gradient(startColorstr='#6356ff',endColorstr='#75b6ff',GradientType=0);
,現在我們要這樣複雜的樣式應用到我們的文檔HTML和身體。如何使用jQuery執行此類事情?
不應該引用實際值或什麼?編輯:哦,等等......這是一個CSS定義?我相信OP問「生成的字符串」以應用爲CSS ... – hayavuk 2012-02-25 22:21:22
我不認爲這個答案。他們將CSS作爲一個javascript字符串,我假設他們想知道如何通過javascript應用它。 – jfriend00 2012-02-25 22:23:16