Doctrine中的簡單IF測試語句

Question

Doctrine是否支持IF語句？我得到以下錯誤：

Expected known function, got 'IF' 

而與IF執行這個查詢：

$qb->select("c.id, IF(c.type_id LIKE 9, c.name, c.lastname) as name") 

它正常工作，而重新用純SQL。任何解決方法？

Answer 1

是在教義if語句不支持您可以將其轉換爲case when

IF(c.type_id LIKE 9, c.name, c.lastname) as name 

到

case when c.type_id = 9 then c.name else c.lastname end as name 

UPDATE： 從註釋沒有concat功能是允許在case-when

答案是非常允許的。下面是一個例子

mysql> select * from timesheets ; 
+-----------+-------+----------+ 
| client_id | hours | category | 
+-----------+-------+----------+ 
|   1 | 1.50 | onsite | 
|   1 | 1.50 | onsite | 
|   1 | 1.00 | remote | 
|   2 | 1.50 | remote | 
+-----------+-------+----------+ 
4 rows in set (0.00 sec) 

mysql> select 
case when category = 'onsite' then concat('ON',' ',hours) else hours 
end as dd from timesheets ; 
+---------+ 
| dd  | 
+---------+ 
| ON 1.50 | 
| ON 1.50 | 
| 1.00 | 
| 1.50 | 
+---------+ 
4 rows in set (0.00 sec)