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我想做一個腳本,找到用戶的當前位置,並在頁面重新載入後設置一個隨機的座標。我可以啓動地圖和隨機座標功能,但地理位置似乎沒有定位我的位置,所有它雖然在infowindow中打印出消息?地理位置谷歌地圖jquery
var map;
var pos;
function initialize() {
//here is the starting for the map, where it will begin to show
var latlng = new google.maps.LatLng(59.2982762, 17.9970823);
var myOptions = {
zoom: 13,
center: latlng,
mapTypeId: google.maps.MapTypeId.ROADMAP
};
var map = new google.maps.Map(document.getElementById('map-canvas'), myOptions);
//geolocation
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(function(position) {
initialLocation = new google.maps.LatLng(position.coords.latitude, position.coords.longitude);
var infowindow = new google.maps.InfoWindow({
map: map,
position: pos,
content: "You are here"
});
map.setCenter(pos);
}, function() {
handleNoGeolocation(true);
});
}
else {
handleNoGeolocation(false);
}
function handleNoGeolocation(errorflag) {
if (errorflag) {
alert('Geolocation not supported');
initialLocation = stockholm;
}
else {
alert('balblababa');
initialLocation = siberia;
};
var infowindow = new google.maps.InfoWindow(options);
map.setCenter(options, position);
}
//stop geolocation
var flagAreas = [
[59.2967322, 18.0009393],
[59.2980245, 17.9971503],
[59.2981078, 17.9980875],
[59.2982762, 17.9970823],
[59.2987638, 17.9917639],
[59.2987649, 17.9917824],
[59.2987847, 17.9917731],
[59.2988498, 17.991684],
[59.2988503, 17.9981593],
[59.3008233, 18.0041763],
[59.3014033, 18.0068793],
[59.3016619, 18.0137766]
];
var random = flagAreas.sort(function() {
return Math.random() - 0.5 })[0];
var marker = new google.maps.Marker({
position: new google.maps.LatLng(random[0], random[1]),
map: map,
});
}
window.onload = initialize;
</script>
您的infowindow'position'設置爲錯誤的變量,將其設置爲'initialLocation'。此外,不知道你是否知道,但你聲明映射兩次(全局和本地'initialize()') - 沒有問題,因爲一切都發生在'initialize()'範圍內,但沒有良好的做法)。 –
作品非常感謝你! – Chilibiff
不錯,不要忘了'map.setCenter(pos);'也應該改成'map.setCenter(initialLocation);' –