收集字符串值並添加到數組中

Question

我在寫一個應用程序，我想從列表中收集姓名和電話號碼並將其添加到數組中。我該怎麼做呢？我可以檢索名字和姓氏，但我不知道如何在下面的代碼中添加電話號碼，因爲它在不同的for循環。它可能看起來很簡單，但因爲我是新手而被卡住了。

for (i = 0; i < [list count]; i++) 
{ 
    NSString *firstName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonFirstNameProperty); 

    NSString *lastName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonLastNameProperty); 

    NSMutableArray *name = [NSMutableArray array]; 
    if(firstName != nil) 
     [name addObject:firstName]; 

    if(lastName != nil) 
     [name addObject:lastName];*/ 

    [self displaynames:name]; 


    ABMultiValueRef mobile=ABRecordCopyValue(contactPerson, kABPersonPhoneProperty); 

    for (int k=0;k<ABMultiValueGetCount(mobile); k++) 
    { 
     NSString *mobileNo = (__bridge_transfer NSString *)ABMultiValueCopyValueAtIndex(mobile, k); 
     NSLog(@"mobile number: %@",mobileNo);  
    } 
} 

- (void)displaynames:(NSMutableArray*)names 
{ 
    for (NSMutableArray* name in names) 
    { 
     NSLog(@"MyResult:%@ %@",[names objectAtIndex:0],[names objectAtIndex:1]); 
    } 
} 

所以在上面的代碼中，我能夠從列表中獲得的第一個名字和姓氏，並把它們添加到陣列中，類似如何獲取手機號碼，並添加到同一個陣列，並獲得導致displayNames:函數，因爲它是另一個for循環。有人可以編輯代碼並告訴我在上面的代碼中必須做出什麼改變。爲什麼所有結果都顯示兩次？

Answer 1

NSMutableArray *contactList=[[NSMutableArray alloc] init]; 

for (int i=0; i<4; i++) { 

    NSMutableDictionary *contactInfo=[[NSMutableDictionary alloc] init]; 

    for (int i = 0; i < [list count]; i++) 
    { 
     NSString *firstName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonFirstNameProperty); 
     NSString *lastName = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonLastNameProperty); 

     if (![firstName isEqualToString:@""]) { 
      [contactInfo setValue:firstName forKey:@"firstName"]; 
     } 

     if (![lastName isEqualToString:@""]) { 
      [contactInfo setValue:lastName forKey:@"lastName"]; 
     } 

     NSMutableArray *mobileNoArray=[[NSMutableArray alloc] initWithCapacity:ABMultiValueGetCount(mobile)]; 

     ABMultiValueRef mobile=ABRecordCopyValue(contactPerson, kABPersonPhoneProperty); 

     for (int k=0;k<ABMultiValueGetCount(mobile); k++) 
     { 
      NSString *mobileNo = (__bridge_transfer NSString *)ABMultiValueCopyValueAtIndex(mobile, k); 
      [mobileNoArray addObject:mobileNo]; 
     } 

     if (mobileNoArray.count!=0) { 
      [contactInfo setObject:mobileNoArray forKey:@"mobileNo"] 
     } 
    } 

    [contactList addObject:contactInfo]; 
    NSLog(@"contact info == %@",contactInfo); 
} 

NSLog(@"contact list array is %@",contactList); 

Answer 2

您可以嘗試在字典中添加用戶信息或創建模型用戶對象並將其存儲在數組中。所以所有的信息都封裝在一個對象中。

self.users = [NSMutableArray array]; 
for (i = 0; i < [list count]; i++) 
{ 
     NSString *firstName = ... 

     NSString *lastName = ... 

     NSString *mobileNumber = ... 

     NSMutableDictionary *userInfo = [NSMutableDictionary dictionary]; 
     if(firstName) 
      userInfo[@"FirstName"] = firstName; 
     if(lastName) 
      userInfo[@"LastName"] = lastName; 
     if(mobileNumber) 
      userInfo[@"MobileNumber"] = mobileNumber; 

     [self.users addObject:userInfo]; 

    } 

您可以枚舉使用

[self.users enumerateObjectsUsingBlock:^(NSDictionary * userInfo, NSUInteger idx, BOOL *stop) { 

     NSString *firstName = userInfo[@"FirstName"]; 
     NSString *mobileNumber = userInfo[@"MobileNumber"]; 

    }]; 

搜索單個用戶的名稱

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"FirstName == %@",@"aUserName"]; 
NSDictionary *userInfo = [[self.users filteredArrayUsingPredicate:predicate]lastObject]; 

Answer 3

所以，而是採用Array你必須使用Dictionary存儲FirstName, LastName and MobileNo與keyvalue對。如果您有使用Array作爲上層多個用戶，意味着新增用戶字典進入陣列和當過你想要一個用戶寫代碼：

for(NSDictionary *userDic in yourArray) 
{ 
    NSString *fName = [userDic valueForKey:@"FirstName"]; 
    ... 
} 

這其中的方法之一...

Answer 4

請嘗試以下步驟：

NSMutableArray *firstNames; 
NSMutableArray *LastNames; 
NSMutableArray *Mobile_numbers; 
NSMutableArray *type_array; 
NSMutableArray *firstandlast; 

........

-(void)get_arr 
{ 
ABAddressBookRef addressBook = ABAddressBookCreate(); 
    NSArray *arrayOfPeople = (__bridge_transfer NSArray *)ABAddressBookCopyArrayOfAllPeople(addressBook);  
    NSUInteger index = 0; 
    firstNames = [[NSMutableArray alloc] init]; 
    Mobile_numbers = [[NSMutableArray alloc] init]; 
    type_array=[[NSMutableArray alloc]init ]; 
    LastNames=[[NSMutableArray alloc]init ]; 
    NSMutableArray *firstandlast; 

    @try 
    { 
     for(index = 0; index<=([arrayOfPeople count]-1); index++) 
     { 

      ABRecordRef currentPerson = (__bridge ABRecordRef)[arrayOfPeople objectAtIndex:index]; 

      NSString *type; 

      ABMultiValueRef phones = (ABMultiValueRef)ABRecordCopyValue(currentPerson, kABPersonPhoneProperty); 

      for (int i=0; i < ABMultiValueGetCount(phones); i++) 
      { 

       //NSString *phone = (NSString *)ABMultiValueCopyValueAtIndex(phones, i); 
       ////NSLog(@"%@", phone); 
       mobileLabel = (NSString*)ABMultiValueCopyLabelAtIndex(phones, i); 


       //NSLog(@"MOG:%@",mobileLabel); 


       if([mobileLabel isEqualToString:@"_$!<Mobile>!$_"]||[mobileLabel isEqualToString:@"_$!<Main>!$_"]) 
       { 
        //NSLog(@"mobile:"); 
        type=@"mobile"; 
       } 
       else if ([mobileLabel isEqualToString:@"_$!<Work>!$_"]) 
       { 
        //NSLog(@"Work:"); 
        type=@"Work"; 
       } 
       else if ([mobileLabel isEqualToString:@"_$!<Home>!$_"]) 
       { 
        //NSLog(@"Home:"); 
        type=@"Home"; 
       } 

       else if ([mobileLabel isEqualToString:@"_$!<Other>!$_"]) 
       { 
        //NSLog(@"Other:"); 
        type=@"Other"; 
       } 


       mobile = (NSString*)ABMultiValueCopyValueAtIndex(phones, i); 

       //NSLog(@"GG:%@",mobile); 


       mobile = [mobile stringByReplacingOccurrencesOfString:@"-" 
                      withString:@""]; 

       mobile = [mobile stringByReplacingOccurrencesOfString:@"(" 
                      withString:@""]; 

       mobile = [mobile stringByReplacingOccurrencesOfString:@")" 
                      withString:@""]; 

       mobile = [mobile stringByReplacingOccurrencesOfString:@" " 
                      withString:@""]; 

       [Mobile_numbers addObject:mobile]; 
       [type_array addObject:type]; 

       NSString *currentFirstName = (__bridge_transfer NSString *)ABRecordCopyValue(currentPerson, kABPersonFirstNameProperty); 

       ////NSLog(@"NAME:%@",currentFirstName); 

       if ([currentFirstName length]!=0) 
       { 
        //NSLog(@"NAME:%@",currentFirstName); 
        [firstNames addObject:currentFirstName]; 
       } 
       else 
       { 
        //NSLog(@"NAME:DUMMY"); 
        currentFirstName=@""; 
        [firstNames addObject:currentFirstName]; 
       } 

       NSString *currentLast = (__bridge_transfer NSString *)ABRecordCopyValue(currentPerson, kABPersonLastNameProperty); 

       ////NSLog(@"NAME:%@",currentFirstName); 

       if ([currentLast length]!=0) 
       { 
        //NSLog(@"NAME:%@",currentLast); 
        [LastNames addObject:currentLast]; 
       } 
       else 
       { 
        //NSLog(@"NAME:DUMMY"); 
        currentLast=@""; 
        [LastNames addObject:currentLast]; 
       } 


        NSString *temp_f_l=[NSString stringWithFormat:@"%@ %@",currentFirstName,currentLast]; 
       [firstandlast addObject:temp_f_l]; 
      } 


      NSLog(@"MOB:%@",Mobile_numbers); 
      NSLog(@"TYPE:%@",type_array); 



      NSLog(@"FN:%@",firstNames); 
      NSLog(@"FN:%@",LastNames); 


      NSLog(@"FN&LN:%@",firstandlast); 

     } 

    } 
    @catch (NSException *exception) 
    { 
     //NSLog(@"CATCH"); 


    } 

} 

在我應用。我正在使用此代碼將地址簿內容存儲到數組。我希望它對你有幫助。