我擁有ArrayList對象中XML元素的值。我必須使用以下具有子節點元素的結構來創建XML文件。創建包含多個子元素的XML文件
數字,名稱和級別分別被添加到數組列表對象alNumber,alName和alLevel。值按以下順序添加到數組列表對象中。
alNumber.get(1)=0000000042
alName.get(1)=Test Part2
alLevel.get(1)=1
alNumber.get(2)=0000000022
alName.get(2)=Test3243
alLevel.get(2)=1
alNumber.get(3)=0000000061
alName.get(3)=testpartsub
alLevel.get(3)=1
alNumber.get(4)=0000000083
alName.get(4)=testpartsub4
alLevel.get(4)=2
.......
下面應該是XML文件的輸出:
<?xml version="1.0" encoding="UTF-8"?>
<node name="Test Par1" number="0000000041">
<node name="Test Part2" number="0000000042"/> //Level - 1
<node name="Test3243" number="0000000022"/>
<node name="testpartsub" number="0000000061">
<node name="testpartsub4" number="0000000083"/> //<Level -2
<node name="testpartsub1" number="0000000081">
<node name="Test1" number="0000000001"/> //Level -3
<node name="Testpartsub3" number="0000000082">
<node name="Test2" number="0000000021"/> //Level - 4
</node>
</node>
</node>
<node name="testpartsub2" number="0000000062"/>
<node name="Test Part4" number="0000000044">
<node name="testpart4sub1" number="0000000084"/>
</node>
<node name="Test Part3" number="0000000043">
<node name="Test Part5" number="0000000045"/>
<node name="Test Part6" number="0000000046">
<node name="Test334344" number="0000000047"/>
<node name="Test Part4" number="0000000044">
<node name="testpart4sub1" number="0000000084"/>
</node>
</node>
</node>
<node name="Testpartsub3" number="0000000082">
<node name="Test2" number="0000000021"/>
</node>
</node>
這裏是我的代碼:
DocumentBuilderFactory xmlDocFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder xmlDocBuilder = xmlDocFactory.newDocumentBuilder();
System.out.println("**Creating XML File ...");
xmlDocument = xmlDocBuilder.newDocument();
rootElement = xmlDocument.createElement("node");
rootElement.setAttribute("number", wtpart.getNumber());
rootElement.setAttribute("name", wtpart.getName());
xmlDocument.appendChild(rootElement);
Iterator<Integer> iter = alLevel.iterator();
for (int i=1, j=i+1; i<alNumber.size() && i<alName.size() && i<alLevel.size(); i++,j++) {
if (alLevel.get(i) == 1) {
Element element = xmlDocument.createElement("node");
element.setAttribute("number", alNumber.get(i));
element.setAttribute("name", alName.get(i));
rootElement.appendChild(element);
prevElement = element;
}
else if (j<=i) {
if (alLevel.get(j)>alLevel.get(i)){
if (alLevel.get(j) != 1) {
Element element = xmlDocument.createElement("node");
element.setAttribute("number", alNumber.get(i));
element.setAttribute("name", alName.get(i));
prevElement.appendChild(element);
prevElement = element;
}}
else {
Element element = xmlDocument.createElement("node");
element.setAttribute("number", alNumber.get(i));
element.setAttribute("name", alName.get(i));
prevElement.appendChild(element);
}
}
else {
Element element = xmlDocument.createElement("node");
element.setAttribute("number", alNumber.get(i));
element.setAttribute("name", alName.get(i));
prevElement.appendChild(element);
}
}
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "2");
DOMSource source = new DOMSource(xmlDocument);
StreamResult result = new StreamResult(new File("E:\\temp", "Test.xml"));
transformer.transform(source, result);
好的。但是,你的問題是什麼?你嘗試了什麼?這是你的功課嗎?沒有問號的問題不是問題。 – Obenland
我正在嘗試創建該XML文件。但無法打印所需的格式。 –
對於1級和2級,一切似乎都適合我。但後來失敗了。我認爲你必須重寫你的代碼。我會寫你的想法作爲答案,所以它需要一秒鐘。 – Obenland