對象類__PHP_Incomplete_Class無法轉換爲字符串

嗨，我有這個錯誤「可捕捉的致命錯誤：類__PHP_Incomplete_Class的對象無法轉換爲字符串在C：\ xampp \ htdocs \ ProjectTA \ dao \ CustomerDao.php在線161" 就是這樣，我不知道要解決這個問題，我檢查了所有的一切是沒什麼問題對象類__PHP_Incomplete_Class無法轉換爲字符串

這是我的客戶DAO

public function getOneCustomer($id) { 
     try { 
      $conn = Connection::getConnection(); 
      $query = "select * from Customer c join Company comp on c.Company_IdCompany = comp.IdCompany JOIN City cit ON c.City_Id = cit.IdC WHERE c.IdCustomer = ?"; 
      $stmt = $conn->prepare($query); 
      $stmt->bindParam(1, $id); 
      $stmt->execute(); 
      $row = $stmt->fetch(); 


      $customer = new Customer(); 
      $customer->setIdCustomer($row['IdCustomer']); 
      $customer->setCustomerName($row['CustomerName']); 
      $customer->setPhoneNumber($row['PhoneNumber']); 
      $customer->setBankNumber($row['BankNumber']); 
      $customer->setCAddress($row['AddressC']); 
      $customer->setCEmail($row['EmailC']); 
      $customer->setPassword($row['Password']); 
      $customer->setCustomerStatus($row['CustomerStatus']); 
      $customer->setPhoto($row['Photo']); 

      $company = new Company(); 
      $company->setIdCompany($row['IdCompany']); 
      $company->setCompanyName($row['CompanyName']); 
      $company->setWebsite($row['Website']); 
      $company->setPhone($row['Phone']); 
      $company->setEmail($row['Email']); 
      $company->setAddress($row['Address']); 
      $company->setLogo($row['Logo']); 

      $city = new city(); 
      $city->setIdC($row['IdC']); 
      $city->setNameC($row['NameC']); 

      $customer->setCompany_IdCompany($company); 
      $customer->setCity_Id($city); 
     } catch (PDOexception $e) { 
      echo $e->getMessage(); 
      die(); 
     } 
     $conn = null; 
     return $customer; 
    }

，我想在我的客戶視圖中顯示此

<?php 

if (isset($_SESSION['IdCustomer'])) { 
    $dao = new CustomerDao(); 
    $id = $_SESSION['IdCustomer']; 
    $dataInfo = $dao->getOneCustomer($id); 


echo '<div class="col-md-12"> 
     <div id="fh5co-tab-feature-vertical" class="fh5co-tab"> 
       <ul class="resp-tabs-list hor_1"> 
         <li><i class="fh5co-tab-menu-icon ti-ruler-pencil"></i> Company</li> 
         <li><i class="fh5co-tab-menu-icon ti-paint-bucket"></i> Project & Task</li> 
         <li><i class="fh5co-tab-menu-icon ti-shopping-cart"></i> Proof of Payment</li> 
       </ul> 
       <div class="resp-tabs-container hor_1"> 
        <div> 
         <div class="row"> 
          <div class="col-md-12"> 
            <h2 class="h3">Company</h2> 
          </div> 
          <div class="col-md-6"> 
           <h2>'.$dataInfo->getCustomerName().'</h2> // i want diplay customer name 
          </div> 
         </div> 
        </div> 

        </div> 
       </div> 
      </div> 
     </div>';

}？>

謝謝

來源

2017-03-02 Willy Kurniawan

所以，我有一個辦法解決這個問題。在客戶登錄會話中驗證數據登錄時我錯了

來源

2017-03-11 17:10:30

對象類__PHP_Incomplete_Class無法轉換爲字符串

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