塊需要2個參數，但正則表達式匹配1個參數

Question

這裏有什麼問題？嘗試將以前作者的代碼（使用我的）與下面的步驟定義合併。在第一步定義中調用第一步％時出現以下錯誤。這個錯誤是說接收步驟定義需要兩個參數，即表和@name，它是在其他地方設置的，我只用表user_role值調用它。 ＃FAILS WITH：您的塊需要2個參數，但正則表達式匹配1個參數。

Then I make my person a user with role of "Peak Admin" in Peak 

When(/^I make my person a user with role of "([^"]*)" in Peak$/) do |role| 
    step %{I make my person a user in Peak 
    | user_role | role | } 
end 

Then(/^I make my person a user in Peak$/) do |table| 
    step %{I make the person "#{@name}" a user in Peak 
    | user_role | table.rows_hash[:user_role] |} 
end 

When(/I make the person "([^"]*)" a user in Peak$/) do |person,table| 
    .... 

Answer 1

你不是打電話稱取正確的其它步驟中數據表的步驟 - 看到黃瓜維基 - https://github.com/cucumber/cucumber/wiki/Calling-Steps-from-Step-Definitions#calling-steps-with-multiline-step-arguments

之後，你的第一個步驟變得像

When(/^I make my person a user with role of "([^"]*)" in Peak$/) do |role| 
    step "I make my person a user in Peak", table([ 
    [ "user_role", role] 
    ]) 
end