如何加載子只有指定的屬性在@NamedEntityGraph

我想從數據庫裝載一個UserReference對象，但是從覈查屬性我想加載只有ID，名字和姓氏，從而使userReference看起來會是像這樣：如何加載子只有指定的屬性在@NamedEntityGraph

{ 
    "id": 1, 
    "company": "company1", 
    "companyContactName": "some name", 
    "companyPosition": "programmer", 
    "referenceDate": "02/04/2005", 
    "verifier": { 
     "id":1 
     "firstName": "Jane", 
     "lastName": "Smith" 
     "email":null, 
     "username":null, 
     "office:null, 
     "department":null 
    } 
}

我用於UserReference類的實體圖，但我一個負載使用該用戶具有，包括電子郵件，用戶名，辦公室和部門中的所有信息。有什麼辦法來指定類似EntityGraphType.FETCH到子圖，以便它將只加載ID，名字和lastName的驗證？

這是我UserReferenceRepository：

public interface UserReferenceRepository extends JpaRepository<UserReference, Long>{ 

    @EntityGraph(value = "userReferenceGraph" , type = EntityGraphType.FETCH) 
    UserReference findOne(Long id); 
}

的UserReference類：

@Getter 
@Setter 
@EqualsAndHashCode (exclude = {"id", "verifier"}) 
@ToString(exclude = {"id"}) 
@Entity 
@NamedEntityGraphs({ 
    @NamedEntityGraph(
     name = "userReferenceGraph",  
     attributeNodes = { 
      @NamedAttributeNode(value = "verifier", subgraph = "verifierGraph") 
    }, 
    subgraphs = { 
     @NamedSubgraph( 
      name = "verifierGraph", 
      type = User.class, 
      attributeNodes = { 
       @NamedAttributeNode(value = "id"), 
       @NamedAttributeNode(value = "firstName"), 
       @NamedAttributeNode(value = "lastName")})}) 
}) 

public class UserReference { 

    @Id 
    @GeneratedValue 
    private Long id; 

    @ManyToOne(fetch = FetchType.LAZY) 
    @JoinColumn(name = "user_id", referencedColumnName = "user_id", foreignKey = @ForeignKey (name = "FK_UserReference_UserHRDetails_user_id")) 
    @JsonIgnore 
    private UserHRDetails hrDetails; 

    private String company; 
    private String companyContactName; 
    private String companyPosition; 
    private Date referenceDate; 

    @ManyToOne(fetch = FetchType.LAZY) 
    @JoinColumn(name = "verifier_id") 
    private User verifier; 
}

和用戶：

@Getter @Setter 
@EqualsAndHashCode(exclude = {"id", "department", "company", "authorities", "hrDetails"}) 
@ToString(exclude = {"password"}) 
@Entity 
@AllArgsConstructor 
@Builder 
public class User implements Serializable{ 

    private static final long serialVersionUID = 1L; 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Access(value = AccessType.PROPERTY) 
    private Long id; 

    @Size(max = 50) 
    @Column(name = "first_name", length = 50) 
    private String firstName; 

    @Size(max = 50) 
    @Column(name = "last_name", length = 50) 
    private String lastName; 

    @Column(length = 100, unique = true, nullable = false) 
    private String email; 

    @Column(length = 50, unique = true, nullable = false) 
    private String username; 

    @ManyToOne(fetch = FetchType.EAGER) 
    @JoinColumn(name = "department_id") 
    private Department department; 

    @ManyToOne(fetch = FetchType.EAGER) 
    @JoinColumn(name = "office_id") 
    private Office office; 
}

來源

2016-07-14 user4859999

我想你正在使用傑克遜生成JSON。在這種情況下，這是一場傑克遜vs.實體圖的戰鬥，前者無法贏得這場戰鬥。實體圖只是建立SQL查詢的一個提示，你只能告訴Hibernate不加載某些屬性。在加載基本實體字段時，Hibernate仍然不支持實體圖形，請參閱https://hibernate.atlassian.net/browse/HHH-9270。但主要問題是，Jackson會在JSON生成過程中調用實體中的每個getter，Hibernate會延遲加載它們而不考慮實體圖。我只能提出@JsonIgnore的用法，但這可能不像您需要的那樣靈活。

來源

2017-02-06 02:40:50

如何加載子只有指定的屬性在@NamedEntityGraph

回答

相關問題