打印斐波那契數字在十行中逐行

Question

我寫了一個程序來顯示在java中的斐波那契數列，但現在我想序列中的數字以十進行顯示，這是前一行中的前十個斐波納契數字，在下一行等..... 我一直有真正的問題，使這一可能性。

這是程序：

import java.util.Scanner; 
import java.math.BigInteger; 

class Fibonacci { 

public static void main(String args[]) { 


    System.out.print("Enter number upto which Fibonacci series to print: "); 
    int number = new Scanner(System.in).nextInt(); 

    System.out.println("\n\nFibonacci series upto " + number + " numbers : "); 

    for (int i = 1; i <= number; i++) { 

     System.out.println(fibonacciLoop(i) + " "); 
    } 
} 

public static BigInteger fibonacciLoop(int number) { 
    if (number == 1 || number == 2) { 
     return BigInteger.valueOf(1); 
    } 
    for (int x = 1; x <= number; x++){ 
     return BigInteger.valueOf(x); 
    } 
    BigInteger fibonacci = BigInteger.valueOf(1); 
    BigInteger fibo1 = BigInteger.valueOf(1); 
    BigInteger fibo2 = BigInteger.valueOf(1); 
    for (int i = 3; i <= number; i++) { 
     fibonacci = fibo1.add(fibo2); 
     fibo1 = fibo2; 
     fibo2 = fibonacci; 
    } 
    return fibonacci; 
} 
} 

Answer 1

請注意，您的Fibonaci計算不會因爲for循環以下工作：

for (int x = 1; x <= number; x++){ 
     return BigInteger.valueOf(x); 
    } 

後續會做你要求什麼：

import java.math.BigInteger; 
import java.util.Scanner; 
import java.util.LinkedList; 


public class Test { 

    Test(int number) { 
     System.out.println("\n\nFibonacci series upto " + number + " numbers : "); 
     LinkedList<BigInteger> list = new LinkedList<BigInteger>(); 
     for (int i = 1; i <= number; i++) { 
      list.add(fibonacciLoop(i)); 
      if(list.size() == 10) { 
       printFibo(list); 
       list = new LinkedList<BigInteger>(); 
      } 
     } 
     if(!list.isEmpty()) printFibo(list); 
    } 

    public static void main(String args[]) { 
     System.out.print("Enter number upto which Fibonacci series to print: "); 
     new Test(new Scanner(System.in).nextInt()); 
    } 

    private void printFibo(LinkedList<BigInteger> list) { 
     for(BigInteger fiboNumber : list) { 
      System.out.print(fiboNumber + " "); 
     } 
     System.out.println(""); 
    } 

    public BigInteger fibonacciLoop(int number) { 
     if (number == 1 || number == 2) { 
      return BigInteger.valueOf(1); 
     } 
     BigInteger fibonacci = BigInteger.valueOf(1); 
     BigInteger fibo1 = BigInteger.valueOf(1); 
     BigInteger fibo2 = BigInteger.valueOf(1); 
     for (int i = 3; i <= number; i++) { 
      fibonacci = fibo1.add(fibo2); 
      fibo1 = fibo2; 
      fibo2 = fibonacci; 
     } 
     return fibonacci; 
    } 
} 

Answer 2

print（不println）每個號碼，讓他們在同一行。只要你的計數器i是10的倍數，就開始一個新行。

for (int i = 1; i <= number; i++) { 
    System.out.print(fibonacciLoop(i) + " "); 
    if (i % 10 == 0) 
     System.out.println(); 
} 

Answer 3

if(i % 10 == 0) 
{ 
    System.out.println(); 
} 

或者，如果你想成爲幻想。

System.out.print(fibonacciLoop(i) + " " + (i % 10 == 0? "\n":""));