我正在嘗試圍繞我的公司正在開發的API進行封裝。這是安寧的,使用郵遞員,我可以發送郵件請求到像http://subdomain.dev.myapi.com/api/v1/auth/
這樣的端點,用戶名和密碼爲POST數據,並且我收到一個令牌。所有按預期工作。現在,當我嘗試從PHP執行相同的操作時,我得到一個GuzzleHttp\Psr7\Response
對象,但似乎無法像在郵遞員請求中那樣在其內部的任何位置找到該令牌。Guzzlehttp - 如何從Guzzle 6獲得響應的身體?
相關的代碼如下所示:
$client = new Client(['base_uri' => 'http://companysub.dev.myapi.com/']);
$response = $client->post('api/v1/auth/', [
'form_params' => [
'username' => $user,
'password' => $password
]
]);
var_dump($response); //or $resonse->getBody(), etc...
以上代碼的輸出看起來像(警告,文字的傳入牆):
object(guzzlehttp\psr7\response)#36 (6) {
["reasonphrase":"guzzlehttp\psr7\response":private]=>
string(2) "ok"
["statuscode":"guzzlehttp\psr7\response":private]=>
int(200)
["headers":"guzzlehttp\psr7\response":private]=>
array(9) {
["connection"]=>
array(1) {
[0]=>
string(10) "keep-alive"
}
["server"]=>
array(1) {
[0]=>
string(15) "gunicorn/19.3.0"
}
["date"]=>
array(1) {
[0]=>
string(29) "sat, 30 may 2015 17:22:41 gmt"
}
["transfer-encoding"]=>
array(1) {
[0]=>
string(7) "chunked"
}
["content-type"]=>
array(1) {
[0]=>
string(16) "application/json"
}
["allow"]=>
array(1) {
[0]=>
string(13) "post, options"
}
["x-frame-options"]=>
array(1) {
[0]=>
string(10) "sameorigin"
}
["vary"]=>
array(1) {
[0]=>
string(12) "cookie, host"
}
["via"]=>
array(1) {
[0]=>
string(9) "1.1 vegur"
}
}
["headerlines":"guzzlehttp\psr7\response":private]=>
array(9) {
["connection"]=>
array(1) {
[0]=>
string(10) "keep-alive"
}
["server"]=>
array(1) {
[0]=>
string(15) "gunicorn/19.3.0"
}
["date"]=>
array(1) {
[0]=>
string(29) "sat, 30 may 2015 17:22:41 gmt"
}
["transfer-encoding"]=>
array(1) {
[0]=>
string(7) "chunked"
}
["content-type"]=>
array(1) {
[0]=>
string(16) "application/json"
}
["allow"]=>
array(1) {
[0]=>
string(13) "post, options"
}
["x-frame-options"]=>
array(1) {
[0]=>
string(10) "sameorigin"
}
["vary"]=>
array(1) {
[0]=>
string(12) "cookie, host"
}
["via"]=>
array(1) {
[0]=>
string(9) "1.1 vegur"
}
}
["protocol":"guzzlehttp\psr7\response":private]=>
string(3) "1.1"
["stream":"guzzlehttp\psr7\response":private]=>
object(guzzlehttp\psr7\stream)#27 (7) {
["stream":"guzzlehttp\psr7\stream":private]=>
resource(40) of type (stream)
["size":"guzzlehttp\psr7\stream":private]=>
null
["seekable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["readable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["writable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["uri":"guzzlehttp\psr7\stream":private]=>
string(10) "php://temp"
["custommetadata":"guzzlehttp\psr7\stream":private]=>
array(0) {
}
}
}
從郵差的輸出是這樣的:
{
"data" : {
"token" "fasdfasf-asfasdfasdf-sfasfasf"
}
}
很明顯我錯過了一些關於使用響應對象的問題zzle。 Guzzle響應表明請求中有200個狀態碼,所以我不確定我需要做什麼來檢索返回的數據。
'$響應 - > getBody() - > getContents()'不工作? – Federkun
你美麗的天才@Leggendario。你在你自己的時代是一個傳奇。我不知道我以前沒有找到'getContents()'。 – Greg