從Python輸出獲取一行代碼

Question

因此，在我的last question中，我詢問了如何在RSS提要中解析XML中的鏈接。使用我從這裏與額外的研究相結合收到的援助的想法，我能寫了這個：

def GetRSS(RSSurl): 
    url_info = urllib.urlopen(RSSurl) 
    if (url_info): 
     xmldoc = minidom.parse(url_info) 
    if (xmldoc): 
     channel = xmldoc.getElementsByTagName('channel') 
     for node in channel: 
      item = xmldoc.getElementsByTagName('item') 
      for node in item: 
       alist = xmldoc.getElementsByTagName('link') 
       for a in alist: 
        linktext = a.firstChild.data 
        print linktext 

正如我在其他問題中提到，我寫了這個獲得來自RSS feed on Redlettermedia.com的鏈接。代碼工作正常，我收到的輸出是：

http://redlettermedia.com 
http://redlettermedia.com/half-in-the-bag-b-fest-2012/ 
http://redlettermedia.com/an-update-from-red-letter-media/ 
http://redlettermedia.com/half-in-the-bag-red-tails/ 
http://redlettermedia.com/half-in-the-bag-the-devil-inside-and-flyin-ryan/ 
http://redlettermedia.com/newly-found-episode-iii-review-behind-the-scenes-footage/ 
http://redlettermedia.com/half-in-the-bag-the-girl-with-the-dragon-tattoo-and-2011-re-cap/ 
http://redlettermedia.com/mr-plinetts-indiana-jones-and-the-kingdom-of-the-crystal-skull-review/ 
http://redlettermedia.com/new-mr-plinkett-review-trailer/ 
http://redlettermedia.com/plinkett-fest/ 
http://redlettermedia.com/update/ 
http://redlettermedia.com 
http://redlettermedia.com/half-in-the-bag-b-fest-2012/ 
http://redlettermedia.com/an-update-from-red-letter-media/ 
http://redlettermedia.com/half-in-the-bag-red-tails/ 
http://redlettermedia.com/half-in-the-bag-the-devil-inside-and-flyin-ryan/ 
http://redlettermedia.com/newly-found-episode-iii-review-behind-the-scenes-footage/ 

依此類推。我現在要做的是僅打印最新的更新鏈接作爲結果（這是輸出中的第二行，在這種情況下爲「http://redlettermedia.com/half-in-the-bag-b-fest-2012/」）。我將如何只打印該行？

Answer 1

如果它總是在列表中的第二項，你可以嘗試

url = xmldoc.getElementsByTagName('link')[1].firstChild.data 
print url