2016-12-27 79 views
-2

我的問題在於當我手動滾動文字從列表中選擇它時,它正確顯示了定義。但是,當我鍵入並搜索定義時,它總是顯示我的列表的第一項。我目前正在通過教程學習android,並遇到了這個例子,但無法修復這個bug。這裏是我的代碼:Android:在列表中使用陣列適配器進行搜索

Here's my output picture

public class DbBackend extends DbObject{ 

    public DbBackend(Context context) { 
     super(context); 
    } 

    public String[] dictionaryWords(){ 
     String query = "Select * from dictionary"; 
     Cursor cursor = this.getDbConnection().rawQuery(query, null); 
     ArrayList<String> wordTerms = new ArrayList<String>(); 
     if(cursor.moveToFirst()){ 
      do{ 
       String word = cursor.getString(cursor.getColumnIndexOrThrow("word")); 
       wordTerms.add(word); 
      }while(cursor.moveToNext()); 
     } 
     cursor.close(); 
     String[] dictionaryWords = new String[wordTerms.size()]; 
     dictionaryWords = wordTerms.toArray(dictionaryWords); 
     return dictionaryWords; 
    } 

// 
// public int getIndexByValue(String value){ 
//  S 
// } 
    public QuizObject getQuizById(int quizId){ 

     QuizObject quizObject = null; 
     String query = "select * from dictionary where _id = " + quizId; 
     Cursor cursor = this.getDbConnection().rawQuery(query, null); 
     if(cursor.moveToFirst()){ 
      do{ 
       String word = cursor.getString(cursor.getColumnIndexOrThrow("word")); 
       String meaning = cursor.getString(cursor.getColumnIndexOrThrow("meaning")); 
       quizObject = new QuizObject(word, meaning); 
      }while(cursor.moveToNext()); 
     } 
     cursor.close(); 
     return quizObject; 
    } 
} 

這裏的字典活動

public class DictionaryActivity extends ActionBarActivity { 

    private TextView wordMeaning; 
    private TextToSpeech convertToSpeech; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_dictionary); 

     Intent intent = getIntent(); 
     Bundle bundle = intent.getExtras(); 
     int dictionaryId = bundle.getInt("DICTIONARY_ID"); 
     int id = dictionaryId + 1; 

     TextView word = (TextView)findViewById(R.id.word); 
     wordMeaning = (TextView)findViewById(R.id.dictionary); 
     Button textToSpeech = (Button)findViewById(R.id.button); 

     DbBackend dbBackend = new DbBackend(DictionaryActivity.this); 
     QuizObject allQuizQuestions = dbBackend.getQuizById(id); 

     word.setText(allQuizQuestions.getWord()); 
     wordMeaning.setText(allQuizQuestions.getDefinition()); 



    } 

另一類

public class MainActivity extends ActionBarActivity { 

    private EditText filterText; 
    private ArrayAdapter<String> listAdapter; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     filterText = (EditText)findViewById(R.id.editText); 
     ListView itemList = (ListView)findViewById(R.id.listView); 

     DbBackend dbBackend = new DbBackend(MainActivity.this); 
     String[] terms = dbBackend.dictionaryWords(); 

     listAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, android.R.id.text1, terms); 

     itemList.setAdapter(listAdapter); 
     itemList.setOnItemClickListener(new AdapterView.OnItemClickListener() { 
      @Override 
      public void onItemClick(AdapterView<?> parent, View view, int position, long id) { 
       // make Toast when click 
       Toast.makeText(getApplicationContext(), "Position " + position, Toast.LENGTH_LONG).show(); 

       Intent intent = new Intent(MainActivity.this, DictionaryActivity.class); 
       intent.putExtra("DICTIONARY_ID", id); 
       startActivity(intent); 
      } 
     }); 
+0

有很多的代碼在這裏,其中大部分似乎與你的問題無關。請嘗試縮小代碼的哪部分似乎沒有按照您的意圖進行。如果你無法從所發佈的內容中縮小範圍,這表明你沒有花費足夠的時間來解決它。開始的好地方是點擊項目的地方。 – Karakuri

+0

我很抱歉複製粘貼一切。我現在縮小了代碼的範圍。我試着查看代碼,發現列表的位置沒有移動。無論我搜索什麼,我的MainAcitivity類總是將位置值0發送到另一個顯示活動,並顯示列表中的第一個項目。也許,職位價值尚未更新。我應該通過身份證而不是職位? – user7062312

+0

位置是指它在適配器中的位置,而不是它在數據庫中的位置。當列表被過濾時,適配器將原始列表保存起來,並使用僅包含與過濾條件匹配的項目的列表進行交換。適配器正確報告位置爲零。由於職位無法識別數據,因此您需要使用其他方法來識別該位置的數據。 – Karakuri

回答

2

在這一部分嘗試獲取不字標識

public void onItemClick(AdapterView<?> parent, View view, int position, long id) { 
       // make Toast when click 
       Toast.makeText(getApplicationContext(), "Position " + position, Toast.LENGTH_LONG).show(); 
       String selectedText = (String) parent.getItemAtPosition(position); 
       Intent intent = new Intent(MainActivity.this, DictionaryActivity.class); 
       intent.putExtra("DICTIONARY_ID", selectedText); 
       startActivity(intent); 
      } 

和查詢

String query = "select * from dictionary where _id = " + quizId; 

通過

String query = "select * from dictionary where word = '" + quizId + "'; 

更換remenber的quizId現在在你的列表中的位置的話,

+0

傳遞id或word是不是一樣,因爲它們都來自同一行? – user7062312

+0

所以你說這麼做?字符串selected = terms [position]; intent.putExtra(「DICTIONARY_ID」,選中); – user7062312

+0

當我將查詢更改爲單詞時,它會在空對象引用 – user7062312