從主字典中替換userinput列表元素？

在這裏，我有一個主要的dic，其值由列表清單組成。從主字典中替換userinput列表元素？

每當用戶輸入列表的值，我希望我的程序從主列表中替換那些用戶輸入列表。

我已經嘗試過，它給了我期望的輸出，但它包含很多臨時列表，這是煩人的，有沒有其他pythonic方式來實現相同，而不使用不需要的臨時列表？

輸入DIC：

master_dic = { 
    'First': [[{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], 
       [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}]], 
    'Second': [[{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], 
       [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}]], 
    'Third': [[{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], 
       [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}]], 
    'Forth': [[{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], 
       [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}], [{'A': '#d8', 'B': '#d7'}, {'C': '#d8', 'D': '#d7'}]] 
}

我的代碼：

userinput = [[['First'], ['Forth']], [['Second'], ['First']], ['Third'], ['Forth']] 

outer = [] 
for i in userinput: 
    new = [] 
    if len(i) > 1: 
     temp = [] 
     for j in i: 
      jj = master_dic[j[0]] 
      temp.append(jj) 
     new.append(temp) 
     outer.append(new) 
    else: 
     for k in i: 
      kk = master_dic[k] 
      new.append(kk) 
      outer.append(new) 
data_join = [i[0] for i in outer]

輸出：

[ 
    [[[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]], [[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]]], 

    [[[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]], [[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]]], 

    [[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]], 

    [[{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}], [{'A': '#d8', 'B': '#d7'}, {'D': '#d7', 'C': '#d8'}]] 
]

沒有列表的維持

[ 
    [[[ {First value} ]], [[ {Forth value} ]]], 

    [[[ {Second value} ]],[[ {First value} ]]], 

    [[ {Third value} ]], 

    [[ {Forth value} ]] 
]

來源

2016-09-07 Tarun K

我想這是你想要的

def array_replace(userinput,master_dic): 
    for i,data in enumerate(userinput): 
     if isinstance(data, list): 
      found=array_replace(data,master_dic) 
      if not isinstance(found, list): 
       userinput[i]=master_dic[found] 
     else: 
      return data 
    return userinput

DEMO

希望這有助於

來源

2016-09-07 19:09:34 SarathSprakash

從主字典中替換userinput列表元素？

回答

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