使用GROUP BY寫刪除查詢，HAVING

Question

我有一個mysql查詢GROUP BY，HAVING。

查詢工作正常，現在需要刪除相同的記錄，當我試圖刪除這些記錄時，我得到一個錯誤。

選擇查詢

SELECT * FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30) AND user_id IN (SELECT user_id FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30) GROUP BY user_id HAVING COUNT(1) > 100) ORDER BY id ASC LIMIT 200 

刪除查詢

DELETE FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30) AND user_id IN (SELECT user_id FROM user_location_history WHERE (TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30) GROUP BY user_id HAVING COUNT(1) > 100) ORDER BY id ASC LIMIT 200 

錯誤

錯誤代碼：1093 您不能指定更新目標表 'user_location_history'在FROM子句解決此問題

Answer 1

一種方法是包裹子查詢另一個子查詢：

DELETE FROM user_location_history 
WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30 
     AND 
     user_id IN (
      SELECT user_id 
      FROM (SELECT user_id 
       FROM user_location_history 
       WHERE TIMESTAMPDIFF(DAY, 
            FROM_UNIXTIME(location_date/1000), 
            SYSDATE()) < 30 
       GROUP BY user_id 
       HAVING COUNT(1) > 100) AS t) 
ORDER BY id ASC LIMIT 200 

Answer 2

讓您選擇查詢嵌套子查詢，那麼下面會爲你

DELETE FROM user_location_history 
WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE())>30 
     AND 
     user_id IN 
      (
      select * from 
      (
      SELECT user_id 
      FROM user_location_history 
      WHERE TIMESTAMPDIFF(DAY,FROM_UNIXTIME(location_date/1000),SYSDATE()) < 30 
      GROUP BY user_id HAVING COUNT(1) > 100 
      )t 
     ) 
ORDER BY id ASC LIMIT 200