從PHP數據庫中提取數據錯誤

Question

我正在使用此代碼從我的數據庫中提取數據，但它不起作用。有任何想法嗎？

Code: 
<?php 

$db = new mysqli($host,$user,$pass,$name); 

/* check connection */ 
if (mysqli_connect_errno()) { 
    printf("Connect failed: %s\n", mysqli_connect_error()); 
    exit(); 
} 
    $query = "SELECT * FROM Sublist WHERE 1 LIMIT 0 , 30"; 
    $result = $mysqli->query($query); 

while($info = mysql_fetch_array($query, MYSQL_ASSOC)) { 
echo $info['scheduled_date']; 
echo "<br>"; 
echo $info['customer_name']; 
echo "<br>"; 
echo $info['status']; 
echo "<br>"; 
echo $info['kaspersky_template']; 
echo "<br>"; 
echo $info['pcpickup_template']; 

} 
?> 

錯誤代碼：致命錯誤：調用一個成員函數查詢（）一個非對象在/home/projectu/public_html/sub/scheduled.php在線20

Answer 1

你不平均

$result = $db->query($query); 

其次

while ($info = mysqli_fetch_array($result)) {