基本上你需要迭代模型的屬性和它們的鍵和值與過濾器的屬性。
self.models = _.filter(self.models, function (model) {
var fits = true; // does this model "fit" the filter?
model = model.toJSON();
_.each(model, function(modelVal, modelKey) {
_.each(filterArr, function(filter) {
if (modelKey === filter.field && modelVal !== filter.filter) {
fits = false
}
}
})
return fits
})
但是,有一點點的下劃線魔法有一個棘手的方法。我不確定它在性能方面是否更好,但它肯定會讓我看起來更好。
// change a bit the way filter is described:
var filter = {Account: '123', Owner: 'Bob'},
// save an array of filter keys (Account, Owner)
filterKeys = _.keys(filter),
// and an array of its values (123, Bob)
filterVals = _.values(filter)
self.models = _.filter(self.models, function (model) {
// pick a subset of model which has the same keys as filter
var filteredSubset = _.pick(model.attributes, filterKeys),
// pick values of this subset
subsetValues = _.values(filteredSubset)
// this values have to be equal to filter's values
// (use .join() to turn array to string before comparison due to references)
return filteredVals.join() === subsetValues.join()
})
請注意,在後一種情況下,所有模型必須具有在過濾器中聲明的所有鍵。
如果我是你,我正在尋找一個最可靠的方法,我會重寫第一個例子,但會改變_.each
標準for
循環,一旦第一個「無匹配」值滿足返回false
。
我無法理解您所嘗試的內容。 – fguillen