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我不是程序員,並且知道Ruby語言很少。我有一個從網站獲取產品信息的報廢程序,我試圖添加一個救援代碼來處理HTTP 404錯誤,所以它不會結束報廢,而是繼續下一個產品。如何在我的報廢中處理「404錯誤」?
我需要救援加入到下面的代碼:先進
def initialize(id, log = nil, timeout_threshold = nil)
@log_buffer = nil
# prepare internal logging stream
@log = (!log.nil? and log.is_a?(Logger)) ? log : Logger.new(@log_buffer=StringIO.new)
begin
# store instance url address
@id = id.to_s
@url = Link::base_url + 'en-US/item_' + @id + '.htm'
# set remote timeout threshold
@timeout_threshold = (timeout_threshold.to_i > 0) ? timeout_threshold.to_i : 15
@timeout = false
@expired = false
if url_verify
Timeout::timeout(@timeout_threshold) {
Mechanize.html_parser = Nokogiri::HTML
@@agent = Agent.instance
###TODO: [optional?] login
###TODO: [optional?] or login iff pricing not present?
###TODO: Agent.get(user login page)
###TODO: Agent.fill in user/pswd
###TODO: Agent.submit
@html = @@agent.get(url)
@log.info("Alamode Product #{@id.to_s}: Load #{url.to_s}")
@specification = parse_specifications
@quantity, @mapped_quantity = parse_quantities
@price = parse_price
@valid = true
# check parsed page
if @specification.size.zero? and @quantity.size.zero?
@valid = false
@expired = true
@log.warn("Alamode Product #{@id.to_s}: #{url.to_s} unscrappable (product no longer available?)")
else
@log.info("stAlamode Product #{@id.to_s}: #{url.to_s} successfully parsed")
@log.info(" QTY #{@mapped_quantity.to_s}")
end
}
else
# return error message
@valid = false
@log.error("Alamode Product #{@id.to_s}: #{url.to_s} is not a properly formatted URI address")
end
rescue Timeout::Error
@valid = false
@timeout = true
@log.error("Alamode Product #{@id.to_s}: #{url.to_s} did not respond within allocated time")
end
end
感謝。