我在我的代碼的最後部分我的ofstream變量有問題。我怎樣才能避免丟失信息? 該問題由程序的最後部分生成。ofstream不寫所有的東西 - 截斷的數據
這裏是我得到:
Action Movies
Comedy Movies
Drama Movies
Horror Movies
There are no movies for this genre
Mystery Movies
There are no movies for this genre
Romantic Movies
Adventure Movies
Western Movies
ife 1946 D 130 30 8.6 1946 103101
The Best Years of Our Lives 1946 R 172 181 8.1 1946 17648
Lawrence of Arabia 1962 V 216 48 8.5 1962 80746
For a Few Dollars More 1965 W 132 123 8.2 1965 45515
這裏是我應該得到:
Action Movies
Braveheart 1995 A 177 88 8.3 1995 245089
Batman begins 2005 A 140 110 8.3 2005 275523
Comedy Movies
Amelie 2001 C 122 45 8.5 2001 185124
Singin' in the Rain 1952 C 103 77 8.3 1952 56368
Drama Movies
it's a Wonderful Life 1946 D 130 30 8.6 1946 103101
Horror Movies
There are no movies for this genre
Mystery Movies
There are no movies for this genre
Romantic Movies
The Best Years of Our Lives 1946 R 172 181 8.1 1946 17648
Adventure Movies
Lawrence of Arabia 1962 V 216 48 8.5 1962 80746
Western Movies
For a Few Dollars More 1965 W 132 123 8.2 1965 45515
這裏是我的打印功能:該錯誤必須是在這裏,但我不「知道如何解決它
void movieType::printMovieInfo(char* outFileName)
{
std::ofstream outFile;
if(!outFile.is_open())
outFile.open(outFileName, std::ios::app);
outFile<<name<<" "<<year<<" "<<genre<<" "<<length<<" "<<rank;
outFile<<" "<<weight<<" "<<year<<" "<<votes<<std::endl;
}
編輯於:
void movieType::printMovieInfo(std::ofstream& outFile)
{
outFile<<name<<" "<<year<<" "<<genre<<" "<<length<<" "<<rank;
outFile<<" "<<weight<<" "<<year<<" "<<votes<<std::endl;
}
,並在主要的最後一部分:
ij.printMovieInfo("printList.txt");
改爲
ij.printMovieInfo(outFile);
這裏是我的主要功能:問題是在程序結束時產生
#include "movieType.h"
#include <iostream>
#include <fstream>
#include <string>
#include "PQType.h"
#include "QueType.h"//FIFO queue
using namespace std;
int main()
{
movieType movie[9];
ifstream inFile("movie1.txt");
ofstream outFile("printList.txt");
int i =0;
bool notDone=true;
while (notDone)
{
if (movie[i++].readMovieInfo(inFile)== false)
notDone=false;
}
PQType<movieType> PQqueue(8);
int j=0;
while(!PQqueue.IsFull())
{
PQqueue.Enqueue(movie[j++]);
}
QueType<movieType> fifoQueue[8];
string Genre[8]={"Action", "Comedy", "Drama", "Horror", "Mystery", "Romantic", "Adventure","Western"};
movieType it;
while (!PQqueue.IsEmpty())
{
PQqueue.Dequeue(it);
if (it.getGenre() == 'A')
fifoQueue[0].Enqueue(it);
else if (it.getGenre() == 'C')
fifoQueue[1].Enqueue(it);
else if (it.getGenre() == 'D')
fifoQueue[2].Enqueue(it);
else if (it.getGenre() == 'H')
fifoQueue[3].Enqueue(it);
else if (it.getGenre() == 'M')
fifoQueue[4].Enqueue(it);
else if (it.getGenre() == 'R')
fifoQueue[5].Enqueue(it);
else if (it.getGenre() == 'V')
fifoQueue[6].Enqueue(it);
else if (it.getGenre() == 'W')
fifoQueue[7].Enqueue(it);
}
//Problem is generated here.
movieType ij;
for (int i=0;i<8;++i)
{
outFile<<Genre[i]<<" Movies"<<endl;
if (fifoQueue[i].IsEmpty())
outFile<<"There are no movies for this genre"<<endl;
for(int j=0; fifoQueue[i].IsEmpty() != true; ++j)
{
fifoQueue[i].Dequeue(ij);
ij.printMovieInfo("printList.txt");
}
outFile<<endl;
}
return 0;
}
你爲什麼打開文件兩次?只需將你的流傳遞給printMovieInfo函數即可。 – Aleks
當您從'movie1.txt'讀取每段數據以驗證它正在被正確收集時,您是否嘗試將輸出打印到控制檯? – ChiefTwoPencils