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我從json文件創建了一個水平菜單。但我無法創建子女和子女。當我創建管理員的孩子時,它會回家的孩子。我的JavaScript文件是如何從json創建子子菜單
var data = [{
"menu":[
{
"MenuId":1,
"MenuName":"Home",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":1,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":2,
"MenuName":"New Transaction",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":2,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":3,
"MenuName":"Portfolio",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":3,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":4,
"MenuName":"Analytics",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":4,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":5,
"MenuName":"Instructions",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":5,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":6,
"MenuName":"Data Upload",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":6,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":7,
"MenuName":"Administration",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":null,
"SortOrder":7,
"ModuleId":null,
"Menus":[
{
"MenuId":8,
"MenuName":"Masters",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":7,
"SortOrder":1,
"ModuleId":null,
"Menus":[
{
"MenuId":10,
"MenuName":"Currency",
"MenuLink":"/Currencies/Index",
"Action":"Index",
"Controller":"Currencies",
"ParentID":8,
"SortOrder":1,
"ModuleId":null,
"Menus":{
}
},
{
"MenuId":11,
"MenuName":"Country",
"MenuLink":"/Countries/Index",
"Action":"Index",
"Controller":"Countries",
"ParentID":8,
"SortOrder":2,
"ModuleId":null,
"Menus":{
}
}
]
},
{
"MenuId":9,
"MenuName":"User Management",
"MenuLink":null,
"Action":null,
"Controller":null,
"ParentID":7,
"SortOrder":2,
"ModuleId":null,
"Menus":{
}
}
]
}
]
}
];
$(function() {
for(var i = 0, j = data[0].menu.length; i<j; i++) {
var root_menu = data[0].menu[i];
if(root_menu.hasOwnProperty("MenuId")) {
$("#menu").append('<li><a href="#" class="parent-menu">' + root_menu.MenuName + '</a>');
if(root_menu.hasOwnProperty("Menus") && root_menu.Menus.length > 0) {
$("#menu li").append("<ul class='child-list' id='menu_" + root_menu.MenuId + "'>");
for(var n = 0, m = root_menu.Menus.length; n<m; n++) {
var sub_menu = root_menu.Menus[n];
if(sub_menu.hasOwnProperty("MenuId")) {
$("#menu_" + root_menu.MenuId).append("<li class='menu-child'><a href='#'>" + sub_menu.MenuName + "</a></li>");
}
}
}
$("#menu").append("</ul></li>");
}
}
});
您可以從http://jsfiddle.net/JcU4G/9/這裏的孩子也有一個子兒檢查我的代碼。我如何從json文件中安排孩子和小孩?
沒有爲子菜單子子如何顯示太... – Niths 2013-02-27 10:19:24
沒有問題,只是檢查,如果這個子元素有項目菜單像你這樣的root_menu ......而同樣的邏輯與去年再次應用。 – 2013-02-27 10:39:32
我沒有得到你 – Niths 2013-02-27 10:40:23