2016-07-14 39 views
0

我使用c:\​​ tmp中的以下代碼在C++中創建了數據庫。還創建了表並可以在C++中訪問表。但是當我嘗試通過SQLite命令行訪問該表時,我得到「沒有這樣的表」的錯誤。無法訪問SQLite上命令行上的表

這是我如何用C創建數據庫++

rc = sqlite3_open_v2("file:///C:/tmp/myTest1.db", &db, SQLITE_OPEN_READWRITE | SQLITE_OPEN_CREATE| SQLITE_OPEN_URI, NULL); 
    if(rc){ 
     printf( "Can't open database: %s\n", sqlite3_errmsg(db)); 
     return(0); 
    }else{ 
     printf( "Opened database successfully\n"); 
    } 

    /* Create SQL statement */ 
    sql = "CREATE TABLE LoadDates(" \ 
    "ID   TEXT NOT NULL," \ 
    "DT   INT  NOT NULL );"; 

    /* Execute SQL statement */ 
    rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg); 
    if(rc != SQLITE_OK){ 
     printf( "SQL error: %s\n", zErrMsg); 
     sqlite3_free(zErrMsg); 
    }else{ 
     printf( "Table created successfully\n"); 
} 

sql = "INSERT INTO LoadDates (ID,DT) " \ 
    "VALUES ('A1', 20160701); " \ 
    "INSERT INTO LoadDates (ID,DT) " \ 
    "VALUES ('A2', 20160601); " \ 
    "INSERT INTO LoadDates (ID,DT) " \ 
    "VALUES ('A3', 20160801 );"; 

    /* Execute SQL statement */ 
    rc = sqlite3_exec(db, sql, callback, 0, &zErrMsg); 
    if(rc != SQLITE_OK){ 
     printf("SQL error: %s\n", zErrMsg); 
     sqlite3_free(zErrMsg); 
    }else{ 
     printf( "Records created successfully\n"); 
    } 

然後,當我訪問訪問通過命令行我獲得以下錯誤LoadDates。我可以看到myTest1.db在C:\ tmp目錄

c:\tmp>sqlite3.exe myTest1 
SQLite version 3.13.0 2016-05-18 10:57:30 
Enter ".help" for usage hints. 
sqlite> select * from LoadDates; 
Error: no such table: LoadDates 

回答

1

使用調用命令行上sqlite3.exe當完整的文件名:

C:\temp> sqlite3.exe myTest1.db