從PHP中的direcory數組樹中獲取目錄路徑

我有這個任務的麻煩。即時通訊新的PHP。我想我一定用戶遞歸funcruion，但我不明白它是如何使用從PHP中的direcory數組樹中獲取目錄路徑

我有一個這樣的數組：

Array 
(
    [0] => Array 
     (
      [id] => 1 
      [parent_id] => 0 
      [name] => New Folder 
     ) 
    [1] => Array (
      [id] => 2 
      [parent_id] => 1 
      [name] => New Folder2 
     ) 
    [2] => Array 
     (
      [id] => 3 
      [parent_id] => 2 
      [name] => New Folder3 
     ) 
    ...... 
    [5] => Array 
     (
      [id] => 6 
      [parent_id] => 0 
      [name] => New Folder6 
     ) 
    [6] => Array (
      [id] => 7 
      [parent_id] => 6 
      [name] => New Folder7 
     ) 
    [7] => Array 
     (
      [id] => 8 
      [parent_id] => 6 
      [name] => New Folder8 
     ) 
)

我需要建立這樣的豬病的路徑：

/New Folder 
/New Folder/New Folder2 
/New Folder/New Folder2/New Folder3 
... 
/New Folder6 
/New Folder6/New Folder7 
/New Folder6/New Folder8

你能幫我完成這個任務嗎？ Thx。

來源

2013-03-04 kuai6

開始與一些[通用樹構建]（http://stackoverflow.com/questions/8587341/recursive-function-to-generate-multidimensional-array-from-database-result）構建一個多維數組代表樹。利用遞歸函數中新獲得的技能，遍歷該樹並構建路徑。 – deceze 2013-03-04 11:10:21

$txtTree[0]="/"; 

foreach($treeArray as $branch){ 

    if(isset($txtTree[$branch['parent_id']])) { 
     $txtTree[$branch['id']] = $txtTree[$branch['parent_id']] . $branch['name']. "/"; 
    } 
} 

print_r($txtTree); 


Array 
(
    [0] =>/
    [1] => /New Folder/ 
    [2] => /New Folder/New Folder2/ 
    [3] => /New Folder/New Folder2/New Folder3/ 
    [6] => /New Folder6/ 
    [7] => /New Folder6/New Folder7/ 
    [8] => /New Folder6/New Folder8/ 
)

來源

2013-03-04 11:59:42 karmafunk

這太棒了！謝謝！ – kuai6 2013-03-04 12:49:25

從PHP中的direcory數組樹中獲取目錄路徑

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