Post方法與改造永不觸發在OnResponse或在OnFailure

Question

我試圖做一個職位與翻新檢查是否有一些數據存在於服務器中。我的問題是，無論如何都要通過onResponse或OnFailure。代碼從未傳入這兩種方法。我在日誌中沒有出現任何錯誤。如果我調試，代碼到此爲止：call.enqueue（新的回調（），並在下一步走法外

一些幫助將欣賞

代碼：

ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class); 

     Call<User> call = apiService.smsPincodeCheck(getPhoneNuber, email); 
     call.enqueue(new Callback<User>() { 
      @Override 
      public void onResponse(Call<User> call, Response<User> response) { 
       if(response.isSuccess()){ 
        Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show(); 
       } 

       if(response.code() == 401){ 
        Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show(); 
       } 
      } 

      @Override 
      public void onFailure(Call<User> call, Throwable t) { 

      } 
     }); 

接口：

@FormUrlEncoded 
    @POST("api/check") 
    Call<User> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber); 

用戶模型：

public class User implements Serializable { 
    private final static String TAG = "User"; 

    @SerializedName("user") 
    @Expose 
    private Long id; 
    private Long commerceId; 
    private String email; 
    private String name; 
    private String lastname; 
    private String dni; 
    private String companyCharge; 
. 
. 
. Getters and setters 

JSON：

這是我試圖發送到服務器的JSON：

{ 
    "phoneNumber" : "444444444", 
    "email" : "example@example.com" 
} 

編輯1：

Call<ResponseSMS> call = apiService.smsPincodeCheck(getPhoneNuber, email); 
    call.enqueue(new Callback<ResponseSMS>() { 
     @Override 
     public void onResponse(Call<ResponseSMS> call, Response<ResponseSMS> response) { 
      if(response.isSuccess()){ 
       Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show(); 
      } 

      if(response.code() == 401){ 
       Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show(); 
      } 
     } 

     @Override 
     public void onFailure(Call<ResponseSMS> call, Throwable t) { 
      Toast.makeText(RegisterThreeActivity.this, "Failure", Toast.LENGTH_SHORT).show(); 
     } 
    }); 
} 

接口：

Call<ResponseSMS> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber); 

型號：

現在0

public class ResponseSMS { 
    public String response; 
    public int status; 

    public String getResponse() { 
     return response; 
    } 

    public void setResponse(String response) { 
     this.response = response; 
    } 

    public int getStatus() { 
     return status; 
    } 

    public void setStatus(int status) { 
     this.status = status; 
    } 
} 

Answer 1

您將需要一個單獨的模型類來處理Web服務的響應：

public class Response { public String response; public int status; }

，並把這個類來代替User在改造Web服務調用。 1.您smsPincodeCheckApiInterface接口的方法：

在更換User與Response。 2. Call<Response> call = apiService.smsPincodeCheck(getPhoneNuber, email); 3.

call.enqueue(new Callback<Response>() { 
      @Override 
      public void onResponse(Call<Response> call, Response<Response> response) { 
       if(response.isSuccess()){ 
        Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show(); 
       } 

       if(response.code() == 401){ 
        Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show(); 
       } 
      } 

      @Override 
      public void onFailure(Call<Response> call, Throwable t) { 

      } 
     });