我遇到了以下問題: 我想要將我的iPhone應用程序連接到服務器上的數據庫。因此我使用一些(簡單).php文件來管理對數據庫的訪問。插入新的數據已經工作,但我有一些麻煩,提取的數據轉換成的NSMutableArray:NSJSONSerialization - 如何正確地將JSON轉換爲NSArray?
NSURL *contentURL = [NSURL URLWithString:[kHOSTURL stringByAppendingString:kGETBarsURL]];
NSLog(@"URL : %@", contentURL);
NSData *contentData = [NSData dataWithContentsOfURL:contentURL];
NSLog(@"Data : %@", contentData);
NSError *e = nil;
NSMutableArray *jsonArray = [NSJSONSerialization JSONObjectWithData:contentData
options:kNilOptions
error:&e];
NSLog(@"JSON : %@", jsonArray);
NSLog(@"Error : %@", e);
輸出是這樣的(我「XX」縮短「數據:」):
2012-04-28 13:49:37.229 XX[14434:f803] URL : http://xx/getBars.php
2012-04-28 13:49:37.389 XX[14434:f803] Data : <5b7b2275 6e697175 65223a22 34222c22 4e616d65 223a2254 65737422 2c224465 7461696c 73223a22 54686973 49734154 65737422 7d2c7b22 ...>
2012-04-28 13:49:37.390 XX[14434:f803] JSON : (null)
2012-04-28 13:49:37.392 XX[14434:f803] Error : Error Domain=NSCocoaErrorDomain Code=3840 "The operation couldn’t be completed. (Cocoa error 3840.)" (Garbage at end.) UserInfo=0x6daa610 {NSDebugDescription=Garbage at end.}
如果我在瀏覽器中打開網頁,它看起來像這樣:
[{"unique":"4","Name":"Test","Details":"ThisIsATest"},
{"unique":"5","Name":"Test","Details":"ThisIsATest"},
{"unique":"6","Name":"Test","Details":"ThisIsATest"},
{"unique":"7","Name":"Test","Details":"ThisIsATest"},
{"unique":"8","Name":"Test","Details":"ThisIsATest"},
{"unique":"9","Name":"Test","Details":"ThisIsATest"},
{"unique":"10","Name":"Test","Details":"ThisIsATest"}]
我也嘗試過其他選項NSJSONSerialization但沒有工作:(任何人可以幫助我在這裏
?2012-04-28 14:18:30.192 XX[14541:f803] Encoding : [{"unique":"4","Name":"Test","Details":"ThisIsATest"},{"unique":"5","Name":"Test","Details":"ThisIsATest"},{"unique":"6","Name":"Test","Details":"ThisIsATest"},{"unique":"7","Name":"Test","Details":"ThisIsATest"},{"unique":"8","Name":"Test","Details":"ThisIsATest"},{"unique":"9","Name":"Test","Details":"ThisIsATest"},{"unique":"10","Name":"Test","Details":"ThisIsATest"}]
<script type="text/javascript">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-16106315-6']);
_gaq.push(['_setDomainName', '.xx.de']);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript';
ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' :
'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0];
s.parentNode.insertBefore(ga, s);
})();
</script>
錯誤說最後有垃圾數據。你檢查過了嗎? – 2012-04-28 12:06:33
我該如何檢查? :)正如我所提到的,我打開了一個網頁,上面顯示的內容,但似乎好吧不是嗎? – pasql 2012-04-28 12:13:09
嘗試將您的數據轉換爲NSString,打印並查看它是否爲有效的JSON。 'NSLog(@「%@」,[[NSString alloc] initWithData:contentData encoding:NSUTF8StringEncoding]);' – 2012-04-28 12:15:06