Python：找到模式，並通過參考另一行替換字

"E1 Sys1 (PTAC) (G.WNW2)" = SYSTEM   
    TYPE    = PTAC 
    HEAT-SOURCE  = HEAT-PUMP 
    BASEBOARD-SOURCE = NONE 
    SIZING-RATIO  = 1.15 
    MAX-SUPPLY-T  = 90 
    MIN-SUPPLY-T  = 55 
    FAN-SCHEDULE  = "S1 Sys1 (PTAC) Fan Sch" 
    FAN-CONTROL  = TWO-SPEED 
    SUPPLY-STATIC = 0.5 
    SUPPLY-EFF  = 0.33 
    COOLING-EIR  = 0.329152 
    HEATING-EIR  = 0.34025 
    .. 
"E1 WNW Perim Zn (G.WNW2)" = ZONE    
    TYPE    = CONDITIONED 
    MIN-FLOW-RATIO = 1 
    FLOW/AREA  = 0.5 
    OA-FLOW/PER  = 34.6035 
    DESIGN-HEAT-T = 72 
    HEAT-TEMP-SCH = "S1 Sys1 (PTAC) Heat Sch" 
    DESIGN-COOL-T = 75 
    COOL-TEMP-SCH = "S1 Sys1 (PTAC) Cool Sch" 
    SIZING-OPTION = ADJUST-LOADS 
    SPACE   = "Unit 100" 
    ..

我有這個建築能量建模的文本文件。Python：找到模式，並通過參考另一行替換字

系統（E1 Sys1（PTAC）（G.WNW2））和防區（E1 WNW Perim Zn（G.WNW2））是一對。

我想通過引用空格名稱和添加縮寫（例如_sys，_zn）來替換系統名稱和區域名稱，以便易於理解。

空間名稱將位於區域部分的底部。

你能幫我把下面的代碼換成上面的代碼嗎？

"Unit 100_sys" = SYSTEM   
    TYPE    = PTAC 
    HEAT-SOURCE  = HEAT-PUMP 
    BASEBOARD-SOURCE = NONE 
    SIZING-RATIO  = 1.15 
    MAX-SUPPLY-T  = 90 
    MIN-SUPPLY-T  = 55 
    FAN-SCHEDULE  = "S1 Sys1 (PTAC) Fan Sch" 
    FAN-CONTROL  = TWO-SPEED 
    SUPPLY-STATIC = 0.5 
    SUPPLY-EFF  = 0.33 
    COOLING-EIR  = 0.329152 
    HEATING-EIR  = 0.34025 
    .. 
"Unit 100_zn" = ZONE    
    TYPE    = CONDITIONED 
    MIN-FLOW-RATIO = 1 
    FLOW/AREA  = 0.5 
    OA-FLOW/PER  = 34.6035 
    DESIGN-HEAT-T = 72 
    HEAT-TEMP-SCH = "S1 Sys1 (PTAC) Heat Sch" 
    DESIGN-COOL-T = 75 
    COOL-TEMP-SCH = "S1 Sys1 (PTAC) Cool Sch" 
    SIZING-OPTION = ADJUST-LOADS 
    SPACE   = "Unit 100" 
    ..

來源

2017-09-06 Open your eyes

你可以嘗試沿着線的東西：

file = open(file_name, "r") 
infile = file.readlines() 
return_string = "" 

for i in range(len(infile)): 
    infile[i] = infile[i].split() #split into the equation parts 
    if infile[i][0] == "SPACE": #found space element 
     space = ' '.join(infile[i][2:]) #take the name which is the third element and after 
for i in range(len(infile)): 
    if infile[i][2] == "ZONE": 
     infile[i][0] = space + "_zn" 
    elif infile[i][2] == "SYSTEM": 
     infile[i][0] = space + "_sys" 
    return_string += (" ".join(infile[i]) + "\n") #recreating the file 

print (return_string)

此代碼假定它將運行成一條線在空間= XXX，否則會崩潰。希望這有助於

來源

2017-09-06 07:27:56 chngzm

謝謝你的回答。它沒有工作，如果空格名稱包含空白但它可以幫助我如何解決問題。我正在根據你的方法進行工作。謝謝。 –

我已經改變了那部分空間名稱的空間名稱，我認爲它應該適用於這種情況:) – chngzm

使用 regex.sub()功能複雜 正則表達式圖案

短溶液：

，

import re 

with open('yourfile.txt', 'r') as f: 
    pat = re.compile('"[^"]+"(= SYSTEM[\s\S]+)"[^"]+"(= ZONE[\s\S]+)(SPACE\s*=)"([^"]+)"') 
    content = pat.sub('"\\4_sys"\\1"\\4_zn"\\2\\3"\\4"', f.read(), re.M) 
    print(content)

\\1

\\2

\\3

\\4

(...)

輸出：

"Unit 100_sys" = SYSTEM   
    TYPE    = PTAC 
    HEAT-SOURCE  = HEAT-PUMP 
    BASEBOARD-SOURCE = NONE 
    SIZING-RATIO  = 1.15 
    MAX-SUPPLY-T  = 90 
    MIN-SUPPLY-T  = 55 
    FAN-SCHEDULE  = "S1 Sys1 (PTAC) Fan Sch" 
    FAN-CONTROL  = TWO-SPEED 
    SUPPLY-STATIC = 0.5 
    SUPPLY-EFF  = 0.33 
    COOLING-EIR  = 0.329152 
    HEATING-EIR  = 0.34025 
    .. 
"Unit 100_zn" = ZONE    
    TYPE    = CONDITIONED 
    MIN-FLOW-RATIO = 1 
    FLOW/AREA  = 0.5 
    OA-FLOW/PER  = 34.6035 
    DESIGN-HEAT-T = 72 
    HEAT-TEMP-SCH = "S1 Sys1 (PTAC) Heat Sch" 
    DESIGN-COOL-T = 75 
    COOL-TEMP-SCH = "S1 Sys1 (PTAC) Cool Sch" 
    SIZING-OPTION = ADJUST-LOADS 
    SPACE   = "Unit 100" 
    ..

來源

2017-09-06 08:02:45 RomanPerekhrest

感謝您的評論。請給出關於如何使用\\ 1，\\ 2，\\ 3，\\ 4的更多解釋。你認爲這種方法可以用於100個配對區域嗎？謝謝！ –

@Openyoureyes，看我關於被捕獲羣體的解釋說明 – RomanPerekhrest

我基於@chngzm提供的方法解決了這個問題。我分享我的代碼。這不是一個奇特的代碼，但它的作品:)

首先，我做了一個空格名稱列表。我使用try和except函數，因爲文本文件包含一些空白行。

file = open("targetfile.txt", "r") #Read target file 
infile = file.readlines() 
return_string = "" 

# Making list of SPACE names 
space = [] 
for i in range(len(infile)): 
    infile[i] = infile[i].split() #split into the equation parts 
    try: 
     if infile[i][0] == "SPACE": #found space element 
      space.append(" ".join(map(str,infile[i][2:]))) #take the name which is the third element and after 
    except: 
     continue 
space = [x.strip('"') for x in space] #take off quotation marks

然後根據上面列出的列表中的SPACE名稱更改每個SYSTEM和ZONE名稱。

for i in range(len(infile)): 
    try: 
     if infile[i][-1] == "SYSTEM": 
      del infile[i][:-2] 
      infile[i].insert(0,"\""+space[0] + "_sys"+"\"") 
     elif infile[i][-1] == "ZONE": 
      del infile[i][:-2] 
      infile[i].insert(0,"\""+space[0] + "_zn"+"\"") 
      del space[0] #remove used SPACE name 
     return_string += (" ".join(infile[i]) + "\n") #recreating the file 
    except: 
     continue 
print (return_string)

這段代碼給了我的確切要求。如果你讓我知道任何更好的/奇特的方法，我將不勝感激。再次感謝！ @chngzm

來源

2017-09-06 17:57:54

Python：找到模式，並通過參考另一行替換字

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