neo4j spring data無法識別的字段「meta」

Question

我開始使用Neo4j和spring數據。

我可以在數據庫上做一個get但不能創建集合。

當我嘗試使用保存方法時發生此錯誤。這似乎是傑克遜無法識別的領域。我尋找解決方案，但沒有任何工作。

任何人都可以幫助我嗎？

10:52:49.481 [http-nio-8080-exec-2] INFO o.s.d.n.config.Neo4jConfiguration - Initialising Neo4jSession 
10:52:51.617 [http-nio-8080-exec-2] ERROR o.n.o.s.response.RowModelResponse - failed to parse: {"row":[1],"meta":[null]}]} 
10:52:51.694 [http-nio-8080-exec-2] INFO o.s.d.n.config.Neo4jConfiguration - Intercepted exception 
May 13, 2016 10:52:56 AM org.apache.catalina.core.StandardWrapperValve invoke 
SEVERE: Servlet.service() for servlet [DispatcherServlet] in context with path [/ProjetoExemplo] threw exception [Request processing failed; nested exception is java.lang.RuntimeException: com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "meta" (class org.neo4j.ogm.session.result.RowModelResult), not marked as ignorable (one known property: "row"]) 
at [Source: {"row":[1],"meta":[null]}]}; line: 1, column: 20] (through reference chain: org.neo4j.ogm.session.result.RowModelResult["meta"])] with root cause 
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "meta" (class org.neo4j.ogm.session.result.RowModelResult), not marked as ignorable (one known property: "row"]) 
at [Source: {"row":[1],"meta":[null]}]}; line: 1, column: 20] (through reference chain: org.neo4j.ogm.session.result.RowModelResult["meta"]) 
    at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:51) 
    at com.fasterxml.jackson.databind.DeserializationContext.reportUnknownProperty(DeserializationContext.java:731) 
    at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:915) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1292) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1270) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:247) 
    at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:118) 
    at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:3051) 
    at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:2146) 
    at org.neo4j.ogm.session.response.RowModelResponse.next(RowModelResponse.java:45) 
    at org.neo4j.ogm.session.response.SessionResponseHandler.updateObjects(SessionResponseHandler.java:93) 
    at org.neo4j.ogm.session.delegates.SaveDelegate.save(SaveDelegate.java:69) 
    at org.neo4j.ogm.session.delegates.SaveDelegate.save(SaveDelegate.java:43) 
    at org.neo4j.ogm.session.Neo4jSession.save(Neo4jSession.java:386) 

我的類：

@NodeEntity 
@JsonIgnoreProperties(ignoreUnknown = true) 
public class Teste { 

@JsonProperty("id") 
private Long id; 

public Long getId() { 
    return id; 
} 

private String name; 

public Teste(){ 

} 

public String getName() { 
    return name; 
} 

public void setName(String name) { 
    this.name = name; 
} 

@Override 
public int hashCode() { 
    final int prime = 31; 
    int result = 1; 
    result = prime * result + ((id == null) ? 0 : id.hashCode()); 
    return result; 
} 

@Override 
public boolean equals(Object obj) { 
    if (this == obj) 
     return true; 
    if (obj == null) 
     return false; 
    if (getClass() != obj.getClass()) 
     return false; 
    Teste other = (Teste) obj; 
    if (id == null) { 
     if (other.id != null) 
      return false; 
    } else if (!id.equals(other.id)) 
     return false; 
    return true; 
} 

我的電話：

Teste teste1 = new Teste(); 
    teste1.setName("TESTE");   
    testeService.save(teste1); 

Answer 1

看起來你正在使用的Neo4j 3？如果是這樣，那麼您使用的SDN版本可能不兼容。 Neo4j的3.0是與這些兼容：

• SDN 4.2的當前快照：4.2.0.BUILD-SNAPSHOT
• SDN 4.1.1：4.1.1.RELEASE用的Neo4j-OGM 2.0.2