我有一些奇怪的問題實現懶惰分配和添加,如https://eigen.tuxfamily.org/dox/TopicInsideEigenExample.html中所示。在C++中實現懶惰分配時出錯
的代碼是
template<typename Derived> class Base;
template<typename Derived, typename OtherDerived> class SumOp;
template<typename Derived, typename OtherDerived>
class SumOp: public Base<SumOp<Derived, OtherDerived>>{
public:
Derived & lhs;
OtherDerived & rhs;
SumOp(Derived & lhs_, OtherDerived & rhs_):lhs(lhs_), rhs(rhs_){}
double packet(size_t index, Base<OtherDerived>& src){
return lhs.packet(index)+ rhs.packet(index);
}
};
template<typename Derived, typename OtherDerived>
struct Assign{
static Derived& run(Derived & dst, OtherDerived & src){
size_t length = dst.size();
for (size_t index =0; index < length; index++){
dst.copyPacket(index, src);
}
return dst;
}
};
template<typename Derived>
class Base{
public:
Base(){}
Derived& derived(){
return *static_cast<Derived*>(this);
}
const Derived& derived() const{
return *static_cast<const Derived*>(this);
}
template<typename OtherDerived>
SumOp<Derived,OtherDerived> operator+(Base<OtherDerived> & other){
return SumOp<Derived, OtherDerived>(this->derived(), other.derived());
}
template<typename OtherDerived>
Derived & operator=(Base<OtherDerived>& other){
return Assign<Derived, OtherDerived>::run(derived(), other.derived());
}
template<typename OtherDerived>
void copyPacket(size_t index, Base<OtherDerived> & other){
derived().writePacket(index, other.derived().packet(index));
}
};
class Vector: public Base<Vector> {
public:
double * data;
size_t nRow;
Vector(size_t nRow_):nRow(nRow_){
data = (double *)malloc(sizeof(double)*nRow);
}
~Vector(){
free(data);
}
template<typename OtherDerived>
Vector& operator=(Base<OtherDerived>& other){
return Base<Vector>::operator=(other);
}
size_t size(){
return nRow;
}
void writePacket(size_t index, double src){
data[index] = src;
}
double packet(size_t index){
return data[index];
}
};
總之,問題的關鍵在於,當我在Vector類,其中編譯器抱怨,我已經通過了左值Base<SumOp<Vector, Vector>>
到運營商,而不是SumOp<Vector, Vector>&
調用operator=
。後者是在撥打operator+
時創建的,後者返回SumOp<Vector, Vector>
。
編譯器錯誤是
no known conversion for argument 1 from ‘SumOp<Vector, Vector>’ to ‘Base<SumOp<Vector, Vector> >&’
我不知道爲什麼在本徵的實現是OK,以及如何解決這個問題。
感謝您的幫助。
編輯
當我打電話以下功能
void test_vector(){
Vector a(10), b(10), c(10);
for (int i=0;i<10;i++){
a.data[i]=1.0;
b.data[i]=1.0;
}
//This is very it goes wrong
c = a+b;
for (int i =0 ; i<10;i++){
std::cout << c.data[i] << std::endl;
}
};
相剋,會出現問題++ - 6錯誤讀取
invalid initialization of non-const reference of type ‘Base<SumOp<Vector, Vector> >&’ from an rvalue of type ‘Base<SumOp<Vector, Vector> >’
c = a+b;
~^~
In file included from /home/ran/Desktop/experiment/PointerMatrix/vector.cpp:6:0:
/home/ran/Desktop/experiment/PointerMatrix/vector.h:76:21: note: initializing argument 1 of ‘Vector& Vector::operator=(Base<OtherDerived>&) [with OtherDerived = SumOp<Vector, Vector>]’
Vector& operator=(Base<OtherDerived>& other){
我似乎無法[轉載](http://coliru.stacked-crooked.com/a/20b82584350dab32)你的問題,既GCC 6.1和叮噹3.8 – WhiZTiM
讓我試用gcc6 –
已經做了〜謝謝非常想提醒 –