2013-09-25 110 views

回答

6
$dt = new DateTime('2013-05-07'); 
echo $dt->format('j F Y'); 

作爲PHP 5.4的

echo (new DateTime('2013-05-07'))->format('j F Y'); 

PHP Date Format

3
echo date('j F Y', strtotime("2013-05-07")); 
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