2013-03-18 69 views
-3

警告:mysql_fetch_assoc()預計參數1是資源, 整數在F中給出:\軟件\ XAMPP \ htdocs中\上線14 連接錯誤錯誤而執行該PHP文件

登錄-check.php

代碼:

<?php 
session_start(); 
if(isset($_SESSION['username'])) 
{ 
header("location:home.php"); 
} 
else 
{ 
$user=$_POST['mailid']; 
$pass=$_POST['password']; 
$con=mysqli_connect("127.0.0.1","rahulk","","weltit"); 
$get=mysqli_query($con,"SELECT * FROM mem WHERE mailid='$user' AND password='$pass'"); 
$check=mysqli_num_rows($get); 
if ($result=mysql_fetch_assoc($check)) 
{ 
$check_pass=$result['password']; 
$check_user=$result['mailid']; 
if ($check_pass==$pass && $check_user==$user) 
{ 
echo "matched"; 
} 
else 
{ 
echo "wrong pass"; 
} 
} 
else 
{ 
echo "connection error"; 
} 
} 
?> 
+0

重複的可能重複的...... – 2013-03-18 15:25:20

+1

請務必縮進代碼。否則它是不可讀的。 – 2013-03-18 15:25:42

回答

0

mysql_fetch_assoc($check)應該mysql_fetch_assoc($get)。你不能得到行號計數的結果。

0
mysql_fetch_assoc($check) 

上面應該是

mysql_fetch_assoc($get)