如何根據mysql中的日期時間字段獲取最新數據？

Question

我想獲取sql中每個日期時間字段的最新數據。任何人都可以幫我解決這個問題。 這是我的表格結構。

| ID | USER |  TIME   | 
------------------------------------- 
| 2 | abc | 2009-01-01 01:00:00 | 
| 3 | abc | 2009-01-01 22:00:00 | 
| 5 | abc | 2009-01-01 10:00:00 | 
| 6 | xyz | 2009-01-02 01:00:00 | 
| 7 | xyz | 2009-01-02 22:00:00 | 
| 8 | xyz | 2009-01-02 10:00:00 | 

而我想這樣的輸出。

| ID | USER |  TIME   | 
------------------------------------- 
| 3 | abc | 2009-01-01 22:00:00 | 
| 7 | xyz | 2009-01-02 22:00:00 | 

編輯：需求變化。正如我所說的，我希望每個用戶的每個日期的最新記錄。

| ID | USER |  TIME   | 
------------------------------------- 
| 2 | abc | 2009-01-01 01:00:00 | 
| 3 | abc | 2009-01-01 22:00:00 | 
| 5 | abc | 2009-01-01 10:00:00 | 
| 6 | xyz | 2009-01-01 01:00:00 | 
| 7 | xyz | 2009-01-01 22:00:00 | 
| 8 | xyz | 2009-01-01 10:00:00 | 
| 10 | abc | 2009-01-04 09:00:00 | 
| 11 | abc | 2009-01-04 02:00:00 | 
| 15 | xyz | 2009-01-04 04:00:00 | 
| 25 | xyz | 2009-01-04 06:00:00 | 

而我想這樣的輸出。

| ID | USER |  TIME   | 
------------------------------------- 
| 3 | abc | 2009-01-01 22:00:00 | 
| 7 | xyz | 2009-01-01 22:00:00 | 
| 10 | abc | 2009-01-04 09:00:00 | 
| 25 | xyz | 2009-01-04 06:00:00 | 

Answer 1

試試這個：

SELECT ID，用戶，時間FROM tbl_name集團按用戶順序按時間倒序，USER ASC;

Answer 2

試試這個：

SELECT * FROM test GROUP BY name ORDER BY name asc, time DESC LIMIT 2 

SQL Fiddle