所以我剛開始使用小程序,並且當小程序加載時,我正在打開一扇門,並打開兩扇窗戶。當你點擊這些窗戶或門時,他們會關閉。我的問題是,我需要做些什麼來重新打開這些窗戶門。我想我需要以某種方式將布爾變量設置爲False並重繪。我會在哪裏做到這一點。我不需要你們爲我寫代碼,我只想知道我該怎麼做。Java House小程序
由於時間提前,
裏克
import java.awt.*;
import java.awt.event.*;
import java.applet.*;
/**
Rick Armstrong
Chapter 14 - House Applet
*/
public class HouseApplet extends Applet {
boolean leftWin, rightWin, door;
public void init()
{
leftWin = false;
rightWin = false;
door = false;
setBackground(Color.white);
addMouseListener(new MyMouseListener());
}
public void paint(Graphics g)
{
super.paint(g);
// Draw the house.
g.setColor(Color.black);
g.drawRect(100, 100, 200, 100);
// Draw the roof
g.drawLine(80, 100, 320, 100);
g.drawLine(80, 100, 200, 40);
g.drawLine(200, 40, 320, 100);
// Draw the left window open.
g.fillRect(120, 130, 40, 40);
// Draw the right window open.
g.fillRect(240, 130, 40, 40);
// Draw the door open.
g.fillRect(180, 130, 40, 70);
if (leftWin) {
// Draw the left window closed.
g.setColor(Color.white);
g.fillRect(120, 130, 40, 40);
g.setColor(Color.black);
g.drawRect(120, 130, 40, 40);
g.drawLine(140, 130, 140, 170);
g.drawLine(120, 150, 160, 150);
}
if (rightWin) {
// Draw the right window closed.
g.setColor(Color.white);
g.fillRect(240, 130, 40, 40);
g.setColor(Color.black);
g.drawRect(240, 130, 40, 40);
g.drawLine(260, 130, 260, 170);
g.drawLine(240, 150, 280, 150);
}
if (door) {
// Draw the door closed.
g.setColor(Color.white);
g.fillRect(180, 130, 40, 70);
g.setColor(Color.black);
g.drawRect(180, 130, 40, 70);
g.fillOval(210, 165, 07, 07);
}
}
private class MyMouseListener implements MouseListener
{
public void mousePressed(MouseEvent e)
{
}
public void mouseClicked(MouseEvent e)
{
int currentx = e.getX();
int currenty = e.getY();
boolean WindowLeft = (currentx >= 120 && currentx < 160 && currenty >= 130 && currenty <= 170);
if (WindowLeft)
{
leftWin = true;
repaint();
}
boolean WindowRight = (currentx >= 240 && currentx < 280 && currenty >= 130 && currenty <= 170);
if (WindowRight)
{
rightWin = true;
repaint();
}
boolean Door = (currentx >= 180 && currentx < 220 && currenty >= 40 && currenty <= 200);
if (Door)
{
door = true;
repaint();
}
else;
}
public void mouseReleased(MouseEvent e)
{
}
public void mouseEntered(MouseEvent e)
{
}
public void mouseExited(MouseEvent e)
{
}
}
}
很好的問題。當我寫它哈哈,它聽起來很好。我會試試Uri。感謝您的回覆。 – HKImpact 2012-04-25 00:29:10
你有幾件事我可以做不同的Uri,我不否認那個哈哈。但是當你告訴我value =!value;那麼這對我來說都是有意義的。發佈後我覺得很蠢。我知道這很容易。非常感謝你! – HKImpact 2012-04-25 00:32:21