程序運行時出錯（Python）

Question

我的程序有問題，是否有人可以幫我修復它？

目的：

在input.txt中：

7 12 
100 

Output.txt的：

84 16 

84是從7 * 12和16是從100-84

這是我現在的代碼：

with open('sitin.txt', 'r') as inpt: 
    numberone = inpt.readlines()[0].split(' ') # Reads and splits numbers in the first line of the txt 
    numbertwo = inpt.readlines()[1] # Reads the second line of the txt file 

product = int(numberone[0])*int(numberone[1]) # Calculates the product 
remainder = int(numbertwo)-product # Calculates the remainder using variable seats 

with open('sitout.txt', 'w') as out: 
    out.write(str(product) + ' ' + str(remainder)) # Writes the results into the txt 

它不輸出任何內容。 有人可以幫忙嗎？ 在此先感謝任何人的幫助！

Answer 1

當你調用inpt.readlines()，你完全通過文件的內容讀sitin.txt，使得隨後到readlines()調用將返回一個空arrary []。

爲了避免這個問題多讀，你可以將文件內容保存到一個變量上的第一次讀，然後分析不同線路需要：

with open('sitin.txt', 'r') as inpt: 
    contents = inpt.readlines() 
    numberone = contents[0].split(' ') 
    numbertwo = contents[1] 

product = int(numberone[0])*int(numberone[1]) 
remainder = int(numbertwo) - product 

with open('sitout.txt', 'w') as out: 
    out.write(str(product) + ' ' + str(remainder)) 

Answer 2

考慮發生了什麼：

with open('sitin.txt', 'r') as inpt: 
    # read *all* of the lines and then take the first one and split it 
    numberone = inpt.readlines()[0].split(' ') 

    # oh dear, we read all the lines already, what will inpt.readlines() do? 
    numbertwo = inpt.readlines()[1] # Reads the second line of the txt file 

我敢肯定，你可以解決你的家庭作業的其餘部分與此提示。