我不得不承認我是編程功能的新手,所以我需要你的幫助。鏈接兩個函數
該代碼應在ANOVA之後提供貝葉斯準則(pBIC),並自動從ANOVA表中讀取必要的信息。
我有兩個功能
## This is function 1
test_pBIC1 <- function(name,c){ ## name is the name of the ANOVA table, e.g. "ANOVA_ALL_wake" and c is the number of conditions
c = c
data = get(name)
i = length(data$ANOVA$Effect)
result1 = data.frame(name,c,i)
return(result1)
}
## ----------------------------------------------------
## I now run and save the result of Function 1
result1 <- test_pBIC1("ANOVA_ALL_wake",3) ## for test
## ----------------------------------------------------
## This is function 2
test_pBIC2 <- function(result1){
name1 <- as.character(result1$name)
data = get(name1)
count <- as.vector(result1$i)
for (i in 1:count){
s = (data$ANOVA$DFd[i]/data$ANOVA$DFn[i])+1
n = s*(result1[2]-1)
SSE1 = data$ANOVA$SSd[i]
SSE0 = data$ANOVA$SSd[i]+data$ANOVA$SSn[i]
deltaBIC = (n * log(SSE1/SSE0))+(data$ANOVA$DFn[i]*log(n))
BF01 = exp(deltaBIC/2)
pH0_D = (BF01/(1+BF01))
pH1_D = (1-pH0_D)
result = data.frame(pH0_D, pH1_D)
colnames(result) <- c("pH0_D", "pH1_D")
rownames(result) <- c(data$ANOVA$Effect[i])
if (i == 1){
result_all <- result
} else {
result_all <- rbind (result_all, result)
}
}
return(result_all)
}
## ------------------------------------------------------
Now I run function 2 and receive the result
test_pBIC2(result1)
現在,雖然這確實是工作,我想這兩個功能相聯繫,所以我只要給的名稱和參數c,仍然最終獲得result_all,即不必在彼此之後運行這兩個功能。
我試圖想出了這個解決方案:
test_pBIC <- function(name,c){ ## pass arguments as: test_pBIC(name = "ANOVA_all_wake", c = 3)
c = c
name = name
result1 = data.frame(name,c)
# return(result1)
test_pBIC1 <- function(result1){
c = as.vector(result1$c)
name1 <- as.character(result1$name)
data = get(name)
i = length(data$ANOVA$Effect)
result2 = data.frame(name,c,i)
# return(result2)
test_pBIC2 <- function(result2){
name1 <- as.character(result2$name)
data = get(name1)
count <- as.numeric(integer$i)
for (i in 1:count){
s = (data$ANOVA$DFd[i]/data$ANOVA$DFn[i])+1
n = s*(result1[2]-1)
SSE1 = data$ANOVA$SSd[i]
SSE0 = data$ANOVA$SSd[i]+data$ANOVA$SSn[i]
deltaBIC = (n * log(SSE1/SSE0))+(data$ANOVA$DFn[i]*log(n))
BF01 = exp(deltaBIC/2)
pH0_D = (BF01/(1+BF01))
pH1_D = (1-pH0_D)
result = data.frame(pH0_D, pH1_D)
colnames(result) <- c("pH0_D", "pH1_D")
rownames(result) <- c(data$ANOVA$Effect[i])
if (i == 1){
result_all <- result
} else {
result_all <- rbind (result_all, result)
}
}
return(result_all)
}
}
}
test_pBIC("ANOVA_all_wake", 3)
不過,我只是得到什麼......我不能發現其中的錯誤:(
謝謝!
你是否已經通過實例輸入一步一步執行了更大的過程,並看到它失敗的地方? – ulfelder