PHP網址參數錯誤

Question

我收到錯誤。

url.com/test.php?id=123&id2=456 

這是我get.php

<?php 

$id = $_GET['id']; 
$id2 = $_GET['id2']; 

?> 

我收到此錯誤的第二個參數

代替& URL獲取的&

錯誤

[23-Feb-2017 03:45:00 UTC] PHP Notice: Undefined index: id2 in /home/xxxx/public_html/url.com/get.php on line 4 

Answer 1

try this.. 
    url.com/test.php?id=" . urlencode($id) . "&id2=" . urlencode($id2); 

Decode: 

    $id= urldecode($_GET['id']); 
    $id2= urldecode($_GET['id2']);