我可以使用函數'count（）'來查找密碼中大寫字母的數量嗎？ （蟒蛇）

Question

當我輸入下面的代碼，它說：

TypeError: must be str, not list

這是否意味着我不能使用功能計數（）或有另一種方式，我可以編程嗎？

password = "CheeseMakesMeHappy" 
uppercase =["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"] 
print (password.count(uppercase)) 

Answer 1

只需檢查密碼中的每個字符，並檢查它是否是大寫字符。 例如：

def count_upper(text): 
    count = 0 
    for c in text: 
     if c.isupper(): 
      count+=1 
    return count 

print count_upper("FoOoObA") 

的另一種方法是使用幾組和位掩碼來計數的獨特大寫字符數。

password = "CheeseMakesMeHappy" 
uppercase = set(["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]) 
print len(set(password)&uppercase) 

的set解決方案無論如何都只能算唯一的字符，但在密碼強度計量的情況下，可能不會是一個壞主意。

Answer 2

問題是方法count()需要一個字符串對象。現在，使用這一行(password.count(uppercase))，您正在有效地將Array對象傳遞給您的函數。看到zeraien的答案是一個好的解決方案。