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在Windows上,這個測試代碼執行:爲什麼寫一個用stdout打開的文件會更快?
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <time.h>
#include <assert.h>
int main() {
// The clock() function returns an approximation of processor time used by the program.
// The value returned is the CPU time used so far as a clock_t;
// to get the number of seconds used, divide by CLOCKS_PER_SEC.
auto buf = new char[1048576]; // 1MB
auto cache = new char[512 * 1024];
// initialize the buffer
for (int i = 0; i < 1048576; ++i)
buf[i] = i;
auto fp_reopen = freopen("data_freopen.bin", "wb", stdout);
assert(fp_reopen != nullptr);
setvbuf(fp_reopen, cache, _IOLBF, 512 * 1024);
auto clock_begin = clock();
for (int i = 0; i < 1000; ++i) {
auto n = fwrite(buf, 1048576, 1, fp_reopen);
assert(n == 1);
}
fflush(fp_reopen);
auto clock_end = clock();
#ifdef _WIN32
freopen("CONOUT$", "w", stdout);
#else
freopen("/dev/tty", "w", stdout);
#endif
printf("write with freopen clocks elapsed: %zu\n", clock_end - clock_begin);
auto fp = fopen("data_fopen.bin", "wb");
assert(fp != nullptr);
setvbuf(fp, cache, _IOLBF, 512 * 1024);
clock_begin = clock();
for (int i = 0; i < 1000; ++i) {
auto n = fwrite(buf, 1048576, 1, fp);
assert(n == 1);
}
fflush(fp);
clock_end = clock();
fclose(fp);
printf("write with fopen clocks elapsed: %zu\n", clock_end - clock_begin);
delete[] buf;
delete[] cache;
getchar();
}
生成這些結果:
write with freopen clocks elapsed: 2767
write with fopen clocks elapsed: 8337
爲什麼?
請將您的代碼作爲問題的一部分,而不是將其作爲異地託管。我們不應該離開Stack Overflow來理解它。 – Chris
只需交換兩個測試,然後再試一次。 –
@Chris很抱歉。我在手機上編輯了這個問題。感謝您的提醒和幫助! – vertextao