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我想知道如何在將視圖分隔成3個文件時在codeigniter中添加活動類。如：如何在codeigniter中添加活動的引導類
- 的header.php
- ... page1.php中page10.php
- footer.php
從這個thread，有沒有辦法如何分離時做的視圖。
這個我的頭看起來像：
<body class="skin-red">
<div class="wrapper">
<header class="main-header">
</header>
<aside class="main-sidebar">
<!-- sidebar: style can be found in sidebar.less -->
<section class="sidebar">
<!-- Sidebar user panel -->
<div class="user-panel">
<div class="pull-left image">
<img src="<?php echo base_url();?>assets/dist/img/admin.png" class="img-circle" alt="User Image" />
</div>
<div class="pull-left info">
<p>Username</p>
<small>Privilage</small>
</div>
</div>
<!-- search form -->
<!-- /.search form -->
<!-- sidebar menu: : style can be found in sidebar.less -->
<ul class="sidebar-menu" id="sidebar">
<li class="header">MAIN NAVIGATION</li>
<li class="treeview">
<a href="#">
<i class="fa fa-users"></i> <span>Users</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="<?php echo base_url(); ?>user_man"><i class="fa fa-chevron-right"></i>User List</a></li>
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-hospital-o"></i> <span>Provider</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="<?php echo base_url();?>provider"><i class="fa fa-chevron-right"></i>Provider List</a></li>
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-book"></i> <span>Product Info</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="<?php echo base_url(); ?>productinfo"><i class="fa fa-chevron-right"></i>List Product Info</a></li>
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-book"></i> <span>Procedure</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="<?php echo base_url(); ?>procedure"><i class="fa fa-headphones"></i>Procedure List</a></li>
<!-- <li><a href="#"><i class="fa fa-user"></i>Link Customer Portal</a></li> -->
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-film"></i> <span>Video Upload</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="#"><i class="fa fa-chevron-right"></i>Video Data</a></li>
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Prosedur</a></li> -->
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Informasi NAB</a></li> -->
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Demo(Video)</a></li> -->
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-camera-retro"></i> <span>Slide Show Wallpaper</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="#"><i class="fa fa-chevron-right"></i>Slide Show Data</a></li>
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Prosedur</a></li> -->
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Informasi NAB</a></li> -->
<!-- <li><a href="#"><i class="fa fa-chevron-right"></i>Demo(Video)</a></li> -->
</ul>
</li>
<li class="treeview">
<a href="#">
<i class="fa fa-camera-retro"></i> <span>Examples</span>
<i class="fa fa-angle-left pull-right"></i>
</a>
<ul class="treeview-menu">
<li><a href="<?php echo base_url();?>user/login"><i class="fa fa-chevron-right"></i>Login</a></li>
</ul>
</li>
</ul>
</section>
<!-- /.sidebar -->
</aside>
</div>
</body>
訪問內容，這是我該怎麼做：
<section class="content">
.....
</section>
，這我頁腳視圖：
</div>
<!-- /.content-wrapper -->
<footer class="main-footer">
<div class="pull-right hidden-xs">
<b>Version</b> 2.0
</div>
<strong>Copyright © 2014-2015</strong> All rights reserved.
</footer>
</div><!-- ./wrapper -->
<script></script>
<script></script>
</body>
</html>
我想要製作，當用戶點擊treeview子菜單時它會變爲活動狀態， 右鍵知道當我點擊treeview子菜單。它將重新加載而不會激活。 在樣品我下載AdminLTE活性類中每個子菜單頁面中定義，如菜單 - <li class="active">submenu</li>
問候， 巴比
cmiiw
============== ==================================
我找到了js代碼，它在.app中。 JS。
$.AdminLTE.tree = function (menu) {
var _this = this;
$("li a", $(menu)).click(function (e) {
//Get the clicked link and the next element
var $this = $(this);
var checkElement = $this.next();
//Check if the next element is a menu and is visible
if ((checkElement.is('.treeview-menu')) && (checkElement.is(':visible'))) {
//Close the menu
checkElement.slideUp('normal', function() {
checkElement.removeClass('menu-open');
//Fix the layout in case the sidebar stretches over the height of the window
//_this.layout.fix();
});
checkElement.parent("li").removeClass("active");
}
//If the menu is not visible
else if ((checkElement.is('.treeview-menu')) && (!checkElement.is(':visible'))) {
//Get the parent menu
var parent = $this.parents('ul').first();
//Close all open menus within the parent
var ul = parent.find('ul:visible').slideUp('normal');
//Remove the menu-open class from the parent
ul.removeClass('menu-open');
//Get the parent li
var parent_li = $this.parent("li");
//Open the target menu and add the menu-open class
checkElement.slideDown('normal', function() {
//Add the class active to the parent li
checkElement.addClass('menu-open');
parent.find('li.act').addClass('active');
// parent_li.addClass('active');
//Fix the layout in case the sidebar stretches over the height of the window
_this.layout.fix();
});
}
//if this isn't a link, prevent the page from being redirected
if (checkElement.is('.treeview-menu')) {
e.preventDefault();
}
});
};
這裏是佈局的第一個模式。 in page.A <li>是活躍的，所以page.B，當我點擊其中一個它變得活躍。 將頁面切分成codeigniter方式後，我分離成3：header，content（body）和footer。 我刪除所有的類標籤<li> ..
我嘗試修改像下面thie：
checkElement.addClass('menu-open');
parent.find('li').on('click', function(){
$(this).addClass('active');
});
它不會工作，如果 難怪能跟大家有一個途徑。
對不起我的英文不好:-D
感謝@kapantzak但它仍然不會工作 –