Laravel查詢不起作用

Question

我想這取決於什麼是從GET進來哪來添加到我的查詢：

public function index($type_id) { 
    $Product = new Product; 
    $Product->where('type_id', $type_id); 
    if(array_key_exists('ages', Input::get())) { 
     $Product->where('age_id', $_GET['ages']); 
    } 
    $products = $Product->get(); 
    $productsPaginated = $Product->where('type_id', $type_id)->paginate(2); 
    return View::make('products.products', array(
       'products' => $products, 
       'productsList' => $productsPaginated 
        ) 
    ); 
} 

但是，所有它做的是帶回每個記錄。

我在做什麼錯？

---

這是我如何使我的過濾器：

$brands = $prices = $ages = $brandsUsed = $agesUsed = array(); 
    $out = ''; 
    foreach ($productsList as $product) { 
     $brands[$product->brands->id] = $product->brands->brand; 
     $brandsUsed[] = $product->brands->id; 
     $prices[] = $product->price; 
     $ages[$product->ages->id] = $product->ages->age; 
     $agesUsed[] = $product->ages->id; 
    } 

    $brandsUsed = array_count_values($brandsUsed); 
    $brands = array_unique($brands); 
    $params = Input::get(); 
    $lastParams = http_build_query($params); 
    unset($params['brand']); 
    $params = http_build_query($params); 
    if (count($brands) > 0) { 
     $out .= '<h5>Brands</h5>'; 
     foreach ($brands as $brandId => $brandName) { 

      if (stristr($lastParams, '&brand=' . $brandId) || stristr($lastParams, 'brand=' . $brandId)) { 
       $out .= '<a class="filter-link" href="' . Request::path() . '?' . $params . '">'; 
      } else { 
       $out .= '<a class="filter-link" href="' . Request::path() . '?' . $params . '&brand=' . $brandId . '">'; 
      } 
      $out .= '<span class="cbox">'; 

      if (stristr($lastParams, '&brand=' . $brandId) || stristr($lastParams, 'brand=' . $brandId)) { 
       $out .= '<span class="cbox-checked"></span>'; 
      } 

      $out .= '</span>'; 
      $out .= $brandName; 
      $out .= ' (' . $brandsUsed[$brandId] . ')'; 
      $out .= '</a>'; 
     } 
    } 

Answer 1

您不能創建查詢對象，你應該這樣來做：

public function index($type_id) { 
    $product = Product::where('type_id', $type_id); 
    if(array_key_exists('ages', Input::get())) { 
     $product->where('age_id', $_GET['ages']); 
    } 
    $productsAll = $product->get(); 
    $productsPaginated = $product->where('type_id', $type_id)->paginate(2); 
    return View::make('products.products', array(
       'products' => $productsAll, 
       'productsList' => $productsPaginated 
        ) 
    ); 
} 

你也應該考慮，如果獲得所有產品和分頁產品是有意義的。如果數據庫中有許多產品，則需要很長時間才能獲得所有產品。我也不確定你想得到什麼$productsPaginated。我想你會在這裏需要建立新的查詢：當你想要得到的產品數量只有一個過濾器

$productsPaginated = Product::where('type_id', $type_id)->paginate(2); 

編輯

，您應該使用這裏：

public function index($type_id) { 
    $product = Product::where('type_id', $type_id); 

    $productCount = $product->count(); 

    if(array_key_exists('ages', Input::get())) { 
     $product->where('age_id', $_GET['ages']); 
    } 
    $productsPaginated = $product->paginate(2); 

    return View::make('products.products', array(
       'productsCount' => $productCount, 
       'productsList' => $productsPaginated 
        ) 
    ); 
}