考慮使用類似這樣的東西。
控制XAML:
<UserControl x:Class="WpfTestBench.OpenFileControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml">
<StackPanel>
<TextBox Text="{Binding RelativeSource={RelativeSource FindAncestor, AncestorType={x:Type UserControl}},
Path=Filename, UpdateSourceTrigger=PropertyChanged}" />
</StackPanel>
</UserControl>
控制代碼隱藏:
using System.Windows;
namespace WpfTestBench
{
public partial class OpenFileControl
{
public static readonly DependencyProperty FilenameProperty =
DependencyProperty.Register("Filename", typeof (string), typeof (OpenFileControl));
public OpenFileControl()
{
InitializeComponent();
}
public string Filename
{
get { return (string)GetValue(FilenameProperty); }
set { SetValue(FilenameProperty, value); }
}
}
}
主要XAML:
<Window x:Class="WpfTestBench.OpenFileWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:wpfTestBench="clr-namespace:WpfTestBench"
Title="OpenFileWindow" Width="300" SizeToContent="Height">
<StackPanel>
<wpfTestBench:OpenFileControl x:Name="In" Filename="{Binding SelectedFilename, UpdateSourceTrigger=PropertyChanged}" />
<wpfTestBench:OpenFileControl x:Name="Out" Filename="{Binding ElementName=In, Path=Filename}" />
</StackPanel>
</Window>
主代碼隱藏:
namespace WpfTestBench
{
public partial class OpenFileWindow
{
public OpenFileWindow()
{
InitializeComponent();
DataContext = this;
}
public string SelectedFilename { get; set; }
}
}
執行結果(輸入後在第一控制的東西):
要知道,使用此語句新UIPropertyMetadata(假)將帶領你的ArgumentException,因爲字符串不能用布爾值初始化。 – Somedust
非常真實,我的錯誤,null應該更好地作爲註冊命令 – Dave