2013-09-30 278 views
0

我已經通過代碼再次手動和使用代碼檢查程序,但無法看到我的錯誤。我正在建立一個註冊頁面,如果任何一個字段留空或者密碼不匹配,這個頁面應該會出錯。表單看起來不錯,但是當我嘗試註冊時,我收到錯誤消息「發生了以下錯誤 - 請輸入密碼,請重試。」無論我輸入什麼密碼,都會發生這種情況。註冊頁面沒有註冊用戶

此外,表單應該記住在給出錯誤消息時輸入的數據,但由於某種原因它會填寫姓氏和電子郵件字段,但不是名字。同樣,在看劇本時我看不出原因。

我正在從一本基本的書--PHP &學習MySQL,這些步驟可能並不是最好的,但我想在完成其他任務之前完成它。

<!DOCTYPE HTML> 
<html lang="en"> 
<head> 
    <meta charset="UTF-8"> 
    <title>Providing a register page</title> 
</head> 
<body> 
<?php 
$page_title = 'Register' ; 
include ('includes/header.html'); 

if ($_SERVER[ 'REQUEST_METHOD' ] == 'POST') { 
    require ('../connect_db.php'); 
    $errors = array() ; 

    if (empty($_POST[ 'first_name' ])) { 
     $errors[] = 'Enter your first name.'; 
    } else { 
     $fn = mysqli_real_escape_string($dbc, trim($_POST[ 'first_name' ])); 
    } 

    if (empty($_POST[ 'last_name' ])) { 
     $errors[] = 'Enter your last name.'; 
    } else { 
     $ln = mysqli_real_escape_string($dbc, trim($_POST[ 'last_name' ])); 
    } 

    if (empty($_POST[ 'email' ])) { 
     $errors[] = 'Enter your email address.'; 
    } else { 
     $e = mysqli_real_escape_string($dbc, trim($_POST[ 'email' ])); 
    } 

    if (!empty($_POST[ 'pass1' ])) { 
     if ($_POST[ 'pass1' ] != $_POST[ 'pass2' ]) { 
      $errors[] = 'Passwords do not match.'; 
     } else { 
      $p = mysqli_real_escape_string($dbc, trim($_POST[ 'pass1' ])); 
     } 
    } else { 
     $errors[] = 'Enter your password.'; 
    } 
    if (empty($errors)) { 
     $q = "SELECT user_id FROM users WHERE email='$e'"; 
     $r = mysqli_query ($dbc , $q); 
      if (mysqli_num_rows($r) != 0) { 
       $errors[] = 'Email address already registered. <a href="login.php">Login</a>'; 
      } 
    } 

    if (empty($errors)) { 
     $q = "INSERT INTO users (first_name, last_name, email, pass, reg_date) VALUES ('$fn', '$ln', '$e', SHA1('$p'), NOW()"; 
     $r = mysqli_query ($dbc , $q); 

     if ($r) { 
      echo '<h1>Registered!</h1>' 
       .'<p>You are now registered.</p>' 
       .'<p><a href="login.php">Login</a></p>'; 
     } 
    mysqli_close($dbc) ; 
    include ('includes/footer.html'); 
    exit(); 
} else { 
    echo '<h1>Error!</h1>' 
     .'<p id="err_msg">The following error(s) occurred:<br>'; 
    foreach ($errors as $msg) { 
     echo " - $msg<br>"; 
    } 
    echo 'Please try again.</p>'; 
    mysqli_close($dbc); 
} 
?> 

<h1>Register</h1> 
<form action="register.php" method="POST"> 
    <p> 
    First Name: <input type="text" name="first_name" 
     value="<?php if (isset($_POST[ ' first_name' ])) echo $_POST[ 'first_name' ] ; ?>"> 
    Last Name: <input type="text" name="last_name" 
     value="<?php if (isset($_POST[ 'last_name' ])) echo $_POST[ 'last_name' ] ; ?>"> 
    </p><p> 
    Email address: <input type="text" name="email" 
     value="<?php if (isset($_POST[ 'email' ])) echo $_POST[ 'email' ] ; ?>"> 
    </p><p> 
    Password: <input type="password name="pass1" 
     value="<?php if (isset($_POST[ 'pass1' ])) echo $_POST[ 'pass1' ] ; ?>"> 
    Password: <input type="password name="pass2" 
     value="<?php if (isset($_POST[ 'pass2' ])) echo $_POST[ 'pass2' ] ; ?>"> 
    </p><p> 
    <input type="submit" value="Register"> </p> 
</form> 
<?php include ('includes/footer.html') ; ?> 
</body> 
</html> 
+0

請使用''

回答

2

你忘記了一個括號 「)

$q = "INSERT INTO users 
(first_name, last_name, email, pass, reg_date) 
VALUES ('$fn', '$ln', '$e', SHA1('$p'), NOW()) " ; 
              ^^ Here 
+0

括號!=括號 –

+0

@RUJordan ..謝謝:) – aldanux

+0

Gotchu brah! ;) –