如何在Python中打印正數的數字的符號+

Question

是否有更好的方法在正數上打印數字的正號？

integer1 = 10 
integer2 = 5 
sign = '' 
total = integer1-integer2 
if total > 0: sign = '+' 
print 'Total:'+sign+str(total) 

0應該返回0沒有+。

Answer 1

>>> print "%+d" % (-1) 
-1 
>>> 
>>> print "%+d" % (1) 
+1 
>>> print "%+d" % (0) 
+0 
>>> 

這裏是the documentation。

** **更新如果因任何原因，你不能使用%運營商，你並不需要的功能：

>>> total = -10; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:-10 
>>> total = 0; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:0 
>>> total = 10; print "Total:" + ["", "+"][total > 0] + str(total) 
Total:+10 
>>> 

Answer 2

使用new string format

>>> '{0:+} number'.format(1) 
'+1 number' 
>>> '{0:+} number'.format(-1) 
'-1 number' 
>>> '{0:+} number'.format(-37) 
'-37 number' 
>>> '{0:+} number'.format(37) 
'+37 number' 
# As the questions ask for it, little trick for not printing it on 0 
>>> number = 1 
>>> '{0:{1}} number'.format(number, '+' if number else '') 
'+1 number' 
>>> number = 0 
>>> '{0:{1}} number'.format(number, '+' if number else '') 
'0 number' 

我們推薦了%運營商