從數據庫中提供selectlist

Question

我想從我的數據庫中填充一個selectlist。我只想要'blogID'這一列來填充它，但是我得到了10個不同的選擇列表，都說「選擇一個」。我不知道如何解決它。

<?php 
error_reporting(E_ALL); ini_set('display_errors', 1); 
$serverName = "localhost"; 
$uid = "*****"; 
$pwd = "*****"; 
$databaseName = "blog"; 

$connectionInfo = array("UID"=>$uid,        
"PWD"=>$pwd,        
"Database"=>$databaseName); 
$con=sqlsrv_connect($serverName, $connectionInfo); 
if ($con) 
{ 
} else { 
die(print_r(sqlsrv_errors(), true)); 
} 
$result = sqlsrv_query($con,"SELECT TOP 10 * FROM blog_posts ORDER BY blogID DESC"); 
while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_BOTH)) 
{ 
?> 
<select> 
<option selected="selected">Choose one</option> 
<?php 
foreach($row['blogID'] as $name) { ?> 
    <option><?= $name['name'] ?></option> 
<?php 
} ?> 
</select> 

<?php } sqlsrv_close($con); ?> 

我做錯了什麼？試圖severeal不同的方法，但這是接近我得到..

Answer 1

只是移動<select>標籤和choose one選項循環之外，並沒有必要foreach循環。這是你的代碼的正確方法。

<?php 
error_reporting(E_ALL); ini_set('display_errors', 1); 
$serverName = "localhost"; 
$uid = "*****"; 
$pwd = "*****"; 
$databaseName = "blog"; 

$connectionInfo = array("UID"=>$uid,        
"PWD"=>$pwd,        
"Database"=>$databaseName); 
$con=sqlsrv_connect($serverName, $connectionInfo); 
if ($con) 
{ 
} else { 
die(print_r(sqlsrv_errors(), true)); 
} 
$result = sqlsrv_query($con,"SELECT TOP 10 * FROM blog_posts ORDER BY blogID DESC"); 
?> 
<select> 
<option selected="selected">Choose one</option> 
<?php 
while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_BOTH)) 
{ 
?> 
<option><?= $row['name'] ?></option> 
<?php 
} 
?> 
</select> 
<?php 
sqlsrv_close($con); ?> 

Answer 2

因爲你正在使用<select> while循環中。

試試這個：

<?php 
    error_reporting(E_ALL); ini_set('display_errors', 1); 
    $serverName = "localhost"; 
    $uid = "*****"; 
    $pwd = "*****"; 
    $databaseName = "blog"; 

    $connectionInfo = array("UID"=>$uid,        
    "PWD"=>$pwd,        
    "Database"=>$databaseName); 
    $con=sqlsrv_connect($serverName, $connectionInfo); 
    if ($con) 
    { 
    } else { 
    die(print_r(sqlsrv_errors(), true)); 
    } 
    $result = sqlsrv_query($con,"SELECT TOP 10 * FROM blog_posts ORDER BY blogID DESC"); 
    ?> 
    <select> 
    <option selected="selected">Choose one</option> 
    <?php 
    while($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_BOTH)) 
    { 
    ?> 
     <option><?= $row['blogID'] ?></option> 
    <?php } 
    ?> 
    </select> 
    <?php 
    sqlsrv_close($con); ?> 

請不要使用短標記在PHP