查詢爲空

Question

我在我的表'stores'中有4個colums - id，store_name，lat，lng。我想顯示30英里半徑內的所有結果。我得到這個：

$lat = '25.7742644'; 
$lng = '-80.1936558'; 
$miles = 30; 

$query = mysql_query("SELECT *, 
      (3959 * acos(cos(radians($lat)) 
      * cos(radians(lat)) 
      * cos(radians(lng) - radians($lng)) 
      + sin(radians($lat)) 
      * sin(radians(lat)))) AS distance 
     FROM stores 
     HAVING distance < $miles 
     ORDER BY distance 
     LIMIT 0, 20 "); 
    $result = mysql_query($query) or die(mysql_error()); 
    while($row=mysql_fetch_array($result)) { 


    echo $store_name; 



    } 

但是當我啓動腳本，我得到「查詢是空的」？

Answer 1

嘗試了這一點：

<?php 

$lng = '-80.1936558'; 
$lat = '25.7742644'; 
$miles = 30; 

$query = "SELECT *, 
(3959 * acos(cos(radians('$lat')) * 
cos(radians(latitude)) * 
cos(radians(lnggitude) - 
radians('$lng')) + 
sin(radians('$lat')) * 
sin(radians(latitude)))) 
AS distance FROM yourtable HAVING distance < '$miles' ORDER BY distance ASC LIMIT 0, 20"; 
$result = mysql_query($query) or die(mysql_error()); 
while($row=mysql_fetch_array($result)){ 
    echo $row["store_name"] . "<br />"; 
} 

?> 

Tutorial link.

Answer 2

$query = mysql_query("SELECT *, ...") 
^^^^^^ ^^^^^^^^^^^ 

$result = mysql_query($query) or die(mysql_error()); 
      ^^^^^^^^^^^ ^^^^^^ 

擺脫其中一個mysql_query。