紅寶石選擇與蘭特方法隨機幾個選項

Question

我的代碼：

alea = ["x", " "] 
num = alea.length 
choice = rand(num) 
veinte = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 

for i in veinte 
    puts alea[choice] 
end 

我希望我的代碼中隨機選擇幾個選項Y沒有唯一的一個。例如：

x 

x 
x 

x 
x 
x 

我該怎麼做？

Answer 1

Array#sample被髮明出來用於此目的：

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10].map do |elem| 
    [elem, [true, false].sample] 
end.to_h 
#⇒ { 
# 1 => true, 
# 10 => false, 
# 2 => true, 
# 3 => true, 
# 4 => false, 
# 5 => true, 
# 6 => false, 
# 7 => true, 
# 8 => false, 
# 9 => false 
#} 

Answer 2

只需編輯代碼：

alea = ["x", " "] 
num = alea.length 
choice = rand(num) 
veinte = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] 
veinte.map { puts alea[rand(alea.length)] } 

Answer 3

你所得到的輸出根據你所編寫的代碼是正確的：

alea = ["x", " "] # => Array on only two elements 
num = alea.length # => 2 
choice = rand(num) # => rand(2) will only output either 0 or 1 which will always output either alea[0] or alea[1] which is " " or "x" 

如果你真的想要一個數組的隨機值，然後我們e @mudasobwa建議的Array類的示例方法

Answer 4

看起來您只需要一定數量的隨機選擇的項目。在這種情況下，只需使用塊形式的Array構造函數：

Array.new(10){ ["x", " "].sample } 

#=>[" ", " ", "x", " ", "x", " ", "x", " ", "x", "x"]