簡單的elif語句

Question

當我運行這段代碼時，它總是進入else。即使我選擇1,2或3.我怎樣才能達到正確的if, elif else陳述？

def main(): 
    name = input("What is your name?") 
    print("Hello", name) 
    choice = int 
    choice = 0 
    choice = input("Please choose a number from the following options: \n 1. Paper \n 2. Rock \n 3. Scissors") 
    print (choice) 

    if choice == 1: 
     print ('You chose number 1') 
    elif choice == 2: 
     print ('You chose number 2') 
    elif choice == 3: 
     print ('You chose number 3') 
    else: 
     print ('Invalid Entry Mush') 
    return 

main() 

Answer 1

或者你可以把你如果報價之間的語句：例如：如果選擇==「1」打印（「NR 1」）的elif選擇==「2」等等..

Answer 2

input返回一個字符串。您需要將其轉換爲int，使得檢查整數您的elif選項觸發：

choice = int(input("Please choose a number from the following options: \n 1. Paper \n 2. Rock \n 3. Scissors")) 

順便說一個前兩行是不必要的。